LCM and HCF Relationship: The terms HCF stands for the highest common factor and LCM stands for the least common multiple. The HCF is the most significant factor of the two numbers or more than two numbers, dividing the number exactly with no remainder. On the contrary, the LCM of two nu...
Question:3 FactorsTreemethod因数树分解法 CanyouwritetheHCFof84and120?Question:4 HowtofindtheLCMof18and42?FindtheLCMandHCFof630and990?Venndiagram TheLCMof6and8is24.Exercises:Doyouwanttochallenge?Summary:1.Whatdidyoulearninthislesson?2.Doyouhaveanyquestions?3.Canyouteachyourfriendssomething?
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Find the HCF and LCM of the following pairs of numbers.36 and 4566 and 132 12, 18 and 20 相关知识点: 试题来源: 解析 \left( 36,45 \right)=9\left( 66,132 \right)=66\left( 12,18,20 \right)=2\left[ 36,45 \right]=180\left[ 66,132 \right]=132\left[ 12,18,20 \right]=...
SOLUTION:Set one x, and the other one y.We have equations from the question:x+8=y384=(2^7)*3however, 384 conclude the (HCF^2),and HCF|LCM. Through the conditiongs, We can let HCF=2^2=4, and LCM=24.so,x= 4m, y=4n, 4m+8=4n. we havem+2=n24|4m, 24|4n...
Properties Of HCF|Method Of Finding HCF|Question Practice|Highest Common Factor(HCF)|OMR View Solution Introduction Of L.C.M.|Question Practice On HCF|OMR|Some Important Properties Of HCF And LCM|Difference Between LCM And HCF|To Find LCM|Properties Of L.C.M. View Solution Recap|Question Pra...
14. 两个数的最大公因数和最小公倍数的乘积为 14. The product of the HCF and LCM of two numbers is384。若这两个数
这意味着x一定是2的倍数。所以，我们可以表示x为2乘以一个未知整数k：x = 2k其中k是任意整数。x可以是任意一个2的倍数。具体的数值取决于k的值。因此，无法确定x的具体数值，但我们可以确定x是2的倍数。如果题目给出了4和x的最小公倍数（LCM），我们就可以确定x的值了。如果题目给出了4和x的...
14.The product of the HCF and LCM of two numbers is384.If one number is 8 more than the other number,then the sum of the two numbers is(A)48(B)40(C)36(D)24(E)1814.The product of the HCF and LCM of two numbers is 384.If one number is 8 more than the other number,then ...
To solve the problem step by step, let's analyze the question: Question: If HCF of m and n is 1, then what are the HCF of m+n and m, and the HCF of m-n and n respectively? (Given that m > n)1. Understanding HCF:<