有时需要将从串口或者网络中接收的数据从字节数组转换成对应的int,float...,double等数据,有时还要考虑大小端字节序以及Swap的问题,发现在C++中需要自己写相关的转换函数,于是/写了一个函数,用于从输入的byte数组中获取指定类型的数据,目前支持int16,int32...; namespace ByteConvertTools { //
-- base/radix is charset string length. -- eg. convert the integer 255 to hex: -- intToBaseN 255 "0123456789abcdef" = "ff" numToBaseN :: Integral n => n -> [Char] -> String numToBaseN num charlst = map (\i -> charlst !! (fromIntegral i)) lst where lst = digits (leng...
-- convert col and row to ['A'..'H'] and [1..4] show (Location (col, row)) = [chr (64 + col), intToDigit row] 自定义类型类 type class 从+ 操作说起,+可以作用于许多类型如整形和浮点型等,其得出的结果类型也不是单一的,这就有个问题:+的类型是什么?如果是(+) :: Integer -> ...
ctDay :: Int, -- Day of the month (1 to 31) ctHour :: Int, -- Hour of the day (0 to 23) ctMin :: Int, -- Minutes (0 to 59) ctSec :: Int, -- Seconds (0 to 61, allowing for leap seconds) ctPicosec :: Integer, -- Picoseconds ctWDay :: Day, -- Day of the wee...
Integral to an Integer toRational Real a => a -> Rational Prelude Convert losslessly to Rational truncate (RealFrac a, Integral b) => a -> b Prelude Truncates number towards zero xor Bits a => a -> a -> a Data.Bits 按位异或 ...
问以haskell表示的NILL值EN我从用户那里获取输入(x)，通过让y= (read x)::Int将其转换为Int，然后...
二进制转换为十进制Haskell给定“decimal”数只包含0和1，我们可以使用recursion来实现：
二进制转换为十进制Haskell给定“decimal”数只包含0和1，我们可以使用recursion来实现：
convertRegToInstValueS::InstValue->StateMachineInstValueconvertRegToInstValueS=\caseIRegLabelreg->dolookupRegisterSrega->returnarunFuncWithInstsS::([InstValue]->InstValue)->[InstValue]->StateMachineInstValuerunFuncWithInstsSfins=donewInsts<-traverseconvertRegToInstValueSinsreturn(fnewInsts) ...
haskell 有可能用中间步骤消除示例的歧义吗？convert :: forall src tgt path. (path ~ ConversionPath...