{@Overridepublicintcompare(Map.Entry<String, Integer> o1,Map.Entry<String, Integer> o2) {//按照value值,重小到大排序 // return o1.getValue() - o2.getValue(); //按照value值,从大到小排序 // return o2.getValue() - o1.getValue(); //按照value值,用compareTo()方法默认是从小到大排序...
public clsaa SortMap { public List<String> sortMapByValue(HashMap<String,Integer> map) { int size = map.size(); ArrayList<Map.Entry<String, Integer>> list = new ArrayList<Map.Entry<String, Integer>>(size); list.addAll(map.entrySet()); ValueComparator vc = new ValueComparator(); Coll...
6.使用自定义比较器,基于entry的值(Entry.getValue()),来排序链表。 7. ele1.getValue(). compareTo(ele2.getValue())——比较这两个值,返回0——如果这两个值完全相同的话;返回1——如果第一个值大于第二个值;返回-1——如果第一个值小于第二个值。 8. Collections.sort()是一个内置方法,仅排序值...
5.1 Sort by Key 首先使用entrySet.stream构造流pipeline,然后调用sorted函数传入内置的Compare,就大公告成了,如下: map.entrySet().stream().sorted(Map.Entry.<String,Integer>comparingByKey()).forEach(System.out::println); 输出: key1=3key2=4key3=5key4=2key5=1 5.2 Sort by Value 类似地,如果要...
private static void sortMapByValues(Map<String, Integer> aMap) { Set<Entry<String,Integer>> mapEntries = aMap.entrySet(); System.out.println("Values and Keys before sorting "); for(Entry<String,Integer> entry : mapEntries) { System.out.println(entry.getValue() + " - "+ entry.getKey...
In this tutorial, we’ll learn how to sort aLinkedHashMapbased on its values. We’ll look at several approaches how to achieve it. 2. Sort With Conversion toList The simplest way to sort aLinkedHashMapby values is to convert it into a list of key-value pairs. After that, we sort ...
result.put(e.getKey(), e.getValue()); } assertEquals(EXPECTED_MY_MAP, result); Let’s walk through the code quickly to understand how it works. First, we wrapentrySet()’sresult in aList.Then, we created an anonymousComparatorto sort the entries by their values and pass it to theCo...
2) 如果仅仅是排序MAP中的KEY和VALUE,则可以: List<Integer> mapKeys = new ArrayList<>(map.keySet()); Collections.sort(mapKeys); List<Student> mapValues = new ArrayList<>(map.values()); Collections.sort(mapValues); 1. 2.
sort(sorted); 输出: [key1, key2, key3, key4, key5] 然后我们可以遍历排好序的List,从map里面拿出相应的Values,这里就不写了,有兴趣的小伙伴可以亲自试试。 3.2 Sort by Value 同样地,我们可以使用HashMap的方法values(),取出所有的Value集合构造List,然后使用Collections.sort排序,代码如下: List<String...
private static void sortMapByValues(Map<String, Integer> aMap) { Set<Entry<String,Integer>> mapEntries = aMap.entrySet();System.out.println("Values and Keys before sorting ");for(Entry<String,Integer> entry : mapEntries) { System.out.println(entry.getValue() + " - "+ entry...