使用 If 条件语句检查 is_Happy_num(n) 的结果。如果语句为 True，则输出给定的数字是是一个快乐数。否则，输出给定的数字不是一个快乐数。defis_Happy_num(n): past = set()while n != 1: n = sum(int(i)**2for i in str(n))if n in past:returnFalse past.add(n)returnTruen = 1...
以下是一个Python实现的Happy Number检测算法: 代码语言:txt 复制 def is_happy_number(n): def get_next(number): total_sum = 0 while number > 0: number, digit = divmod(number, 10) total_sum += digit ** 2 return total_sum seen = set() while n != 1 and n not in seen: seen.add...
代码(Python3) class Solution: def isHappy(self, n: int) -> bool: # used 维护已出现的数字集合 used: Set[int] = set() #当 n 未出现过时,继续计算下一个数 while n not in used: # 标记 n 已出现过 used.add(n) # 计算下一个数,即求 n 的每一位的平方和 nxt: int = 0 #当 n ...
第一篇贡献给python计算happy number~ defcal(n): s=str(n) sum=0foriinrange(len(s)): sum+=int(s[i])**2returnsum a=77#13 139 ok; 4 5 6 not#print (cal(a))defitr(a): log_set=set([a])whilea!=1: temp=cal(a)iftempinlog_set:returnFalse#False but not falseelse: log_set...
链接:https://leetcode-cn.com/problems/happy-number 方法: 方法一:哈希表法-可以收敛到1,肯定是有限迭代,否则一定进入循环 方法二:快慢指针-类似环形链表快慢指针相遇问题 python # 0202.快乐数 classSolution: defisHappy(self,n:int)->bool: """ ...
setData=set() #set datastructure for checking a number is repeated or not. while 1: if n==1: print("{} is a happy number after apply way 2".format(num)) break if n in setData: print("{} is Not a happy number after apply way 2".format(num)) break else: setData.add(n) #...
A happy number is a number def...lintcode-easy-Number of Islands Given a boolean 2D matrix, find the number of islands. Given graph: return 3. ...Lintcode 517. Ugly Number (Easy) (Python) Ugly Number Description: Write a program to check whether a given number is an ugly number...
Happy number: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1, or it loops endlessly in a cycle which does not include 1. Example: 19 is a happy number ...
202. Happy Number刷题笔记 设了个集合来检查是否有中间结果 class Solution: def isHappy(self, n: int) -> bool: def cal_happy(n): sum = 0 while n: sum += (n%10)**2 n = n//10 return sum mid_result = {n} while True:
Happy number: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1, or it loops endlessly in a cycle which does not include 1. An unhappy number is a number that is not happy. ...