squared repeatedly. If this method produces an infinite cycle of numbers containing 4, the number is known as an unhappy number. We will look at the implementation of finding out whether a number is a happy num
LeetCode算法题-Happy Number(Java实现) 这是悦乐书的第188次更新,第190篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第47题(顺位题号是202)。编写算法以确定数字是否“幸福”。 幸福数字是由以下过程定义的数字:从任何正整数开始,将数字替换为其数字的平方和,并重复该过程,直到最后数字等于1。
Java Numbers Exercises Home ↩ Java Exercises Home ↩ PREV :First 10 Catalan Numbers. NEXT :Check Happy or Unhappy Number. Java Code Editor:
replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers. ...
【LeetCode】202. Happy Number 快乐数(Easy)(JAVA) 【LeetCode】202. Happy Number 快乐数(Easy)(JAVA) 题目地址: https://leetcode.com/problems/happy-number/ 题目描述: Write an algorithm to determine if a number n is “happy”. A happy number is a number def......
6. Conclusion In this article, we learned the concept of a happy number and implemented Java methods to determine whether a given number is happy. As always, the complete source code for the examples is availableover on GitHub.
Java Code: importjava.util.HashSet;importjava.util.Scanner;importjava.util.Set;publicclassExample10{publicstaticbooleanisHappy_number(intnum){Set<Integer>unique_num=newHashSet<Integer>();while(unique_num.add(num)){intvalue=0;while(num>0){value+=Math.pow(num%10,2);num/=10;}num=value;}...
每天来一道,面试不卡壳,今天是天天算法陪你成长的第15天。PS:今天发的太晚了,抱歉～ 本题可在LeetCode上OJ,链接 Happy Number, 感谢 @牧码人小鹏 题目描述:Write an algorithm to determine if a number is…
Happy Captcha是一款易于使用的Java验证码软件包,旨在花最短的时间,最少的代码量,实现Web站点的验证码功能。Happy Captcha完全遵循Apache 2.0开源许可协议,你可以自由使用该软件,如您在使用Happy Captcha时发现软件的任何缺陷,欢迎随时与我联系。Happy Capthca的源代码已托管到Github和Gitee,你可以访问下面的链接获取更多...
leetcode 202(easy)--Happy Number 难度:easy Write an algorithm to determine if a number is "happy". A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum...