HAL库 主函数 调用 flash .c 中的HAL_FLASH_Program_HalfWord 函数编译出错 提示未定义，郁闷 0...
So, with 2**3 -> 8 byte alignment and a flash base address of0x08000000, that means that 90720 bytes of flash memory are actually used by the binary. To find out which of the flash sectors are left unused, it is now easy to look the address up directly in the "Flash mem...
protocol));__u8protocol;if(bpf_skb_load_bytes(skb,ETH_HLEN+offsetof(structiphdr,protocol),&protocol,sizeof(protocol))<0)return0;// __u16 h_proto = load_half(skb, offsetof(struct ethhdr, h_proto));__u16raw_h_proto;if(bpf_skb_load_bytes(skb,offsetof(structethhdr,h_proto),&raw_h_p...