第四十三关:Java Subarray 打印出子串和为负数的个数,原串数字个数100以内,如:1 -2 4 - 5 1,输出为9 解决方案: publicstaticvoidmain(String[] args){Scannerscanner=newScanner(System.in);intn=scanner.nextInt();int[] subSum =newint[n]; subSum[0] = scanner.nextInt();for(inti=1;i<n;i+...
It is modulo version of "max sum of contiguous subarray". So similar pattern can be applied too, but with tricks regarding to modulo ops. I checked editorials, and found that,the quick\correct solution requires sharp insight into internal characteristics and mechanism of one problem...which I'...
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Java solution - passes 100% of test cases From myHackerRank solutions. Runtime: O(n) using HashMap and Deque. Space Complexity: O(n) publicclasstest{publicstaticvoidmain(String[]args){HashMap<Integer,Integer>map=newHashMap<>();Deque<Integer>deque=newArrayDeque<>();Scannerscan=newScanner(Sy...
You getting the wrong answer for small test cases, because you have to type cast the value when storing it to long long prod like you just have to replace long long prod = arr[i] * arr[j]; by long long prod = (long)arr[i] * arr[j]; But still this is brute force solution, ...
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