#方法一 但是当string很多的时候,就不行了 string = 'BANANA' S_score = 0 K_score = 0 vowel = 'AEIOU' for cut_len in range(len(string)): for s in range(len(string)): if len(string[s:s+cut_len+1]) == cut_len+1: if string[s:s+cut_len+1][0] in vowel: K_score += 1...
string rtrim(const string &); vector<string> split(const string &); /* * Complete the 'almostSorted' function below. * * The function accepts INTEGER_ARRAY arr as parameter. */ void almostSorted(vector<int> arr) { } int main() { string n_temp; getline(cin, n_temp); int n = st...
hackerrank String 2 Split and Join In Python, a string can be split on a delimiter. Example: Joining a string is simple: Task You are given a string. Split the string on a " " (space) delimiter and join using a ...hackerrank String 7 Designer Door Mat Mr. Vincent works in a ...
Strings String Split and Join 10 Easy Solution.py Strings What's Your Name? 10 Easy Solution.py Strings Mutations 10 Easy Solution.py Strings Find a string 10 Easy Solution.py Strings String Validators 10 Easy Solution.py Strings Text Alignment 10 Easy Solution.py Strings Text Wrap 10 Easy ...
string rtrim(const string &str) { string s(str); s.erase( find_if(s.rbegin(), s.rend(), not1(ptr_fun<int, int>(isspace))).base(), s.end() ); return s; } vector<string> split(const string &str) { vector<string> tokens; string::size_type start = 0; string::size_type ...
问快速字形检验器算法(HackerRank)EN给定两个字符串数组,对于列表(查询)中的每个字符串,确定它在另一...
String Formatting.py String Split and Join.py String Validators.py StringSplit and Join.py Sum and Prod.py Symmetric Difference.py Text Alignment.py Text Wrap.py The Captain's Room .py The Minion Game.py Time Delta.py Transpose and Flatten.py Triangle Quest.py Tuples.py...
Classic DP, and requires you to track optimal path. len1, len2 =map(int, raw_input().strip().split()) a=map(int, raw_input().strip().split()) b=map(int, raw_input().strip().split()) rec= [[(-1, (-1, -1))forxinrange(len1 + 1)]forxinrange(len2 + 1)] ...
Really fun regex one. importre n=int(input()) txt=''for_inrange(n): str=input() txt= txt +str dict={} all= re.findall('<[^/][^<>]*>', txt)foriinrange(len(all)): segs= re.split('', all[i][1:-1])ifnotsegs[0]indict: ...
我的解法是比较愚蠢的直男型解法了,分别处理了WELCOME行和其他行并分别构成每行的字符串,存入列表后再以join的方式输出。再来看大神的解答 Elegant Answer n,m=map(int,input().split())pattern=[('.|.'*(2*i+1)).center(m,'-')foriinrange(n//2)]print('\n'.join(pattern+['WELCOME'.center(m...