; Votes divided by the age in hours to the gravityth power. ; Would be interesting to scale gravity in a slider. (= gravity* 1.8 timebase* 120 front-threshold* 1 nourl-factor* .4 lightweight-factor* .3 ) (def f
hacker-rank-solutions Updated Sep 27, 2021 Python valery1707 / problem-solving Star 0 Code Issues Pull requests This repository contains my solutions to some problems in various online judges, such as LeetCode, HackerRank, E-Olymp, etc. kotlin java leetcode gradle hackerrank leetcode-solution...
问通过二进制搜索爬上主板(Hacker Rank)EN我使用二进制搜索找到每个分数的最佳插入点，并使用索引作为排名...
Python HackerRank coding challenges solved in Rust. rustalgorithmsdata-structureshackerank UpdatedJul 28, 2021 Rust These Contain Some Data Structure & Algorithm Problem Solution of Hacker Rank😏 hackerrankdata-structureshackerrank-datastructures-arrayhackerrank-solutionshackerrank-algorithms-solutionshackerankhack...
相对于下面要讲述的Reddit排序算法,Hacker News的Ranking算法主要区别在于引入了time since submission这个参数,这个参数是不断变化的,从而导致一篇文章的得分不断变化。而Reddit下的一篇文章得分(Rank)是不变的,越新的文章得分越高,所以排序自然可能排在最前面。
The ESP matrix leverages data and analyst insight to identify and rank leading companies in a given technology landscape. EXECUTION STRENGTH ➡MARKET STRENGTH ➡LEADERHIGHFLIEROUTPERFORMERCHALLENGER Vulnerability management Enterprise Tech / Cybersecurity The vulnerability management market helps organizations...
Written by experts who rank among the world's foremost Android security researchers, this book presents vulnerability discovery, analysis, and exploitation tools for the good guys. Following a detailed explanation of how the Android OS works and its overall security architecture, the authors examine ...
NumPy 数组的维数称为秩(rank),秩就是轴的数量,即数组的维度,一维数组的秩为 1,二维数组的秩为 2,以此类推。 在NumPy中,每一个线性的数组称为是一个轴(axis),也就是维度(dimensions)。比如说,二维数组相当于是两个一维数组,其中第一个一维数组中每个元素又是一个一维数组。所以一维数组就是 NumPy 中的轴...
rank[x_root] > self.rank[y_root]: self.parent[y_root] = x_root else: self.parent[y_root] = x_root self.rank[x_root] += 1 def numIslands(grid): if not grid: return 0 uf = UnionFind(grid) directions = [(0, 1), (1, 0), (0, -1), (-1, 0)] for i in range(...
Your couldn't solve it in a normal way, but found a good way to implement slower solution and got your points (it gave you nothing but a higher rank in the standings of Round 1). None of the above. Not critical at all. It could've been critical, if the problem affected someone's...