fastJson1、String转换为JSONObject String param= "{\"age\":\"24\",\"name\":\"cool_summer_moon\"}"; JSONObject jsonObject=JSONObject.parseObject(param); Object object= jsonObject.get("name");2、JSONObject转换为String String jsonString=jsonObject.toJSONString();3、JsonString转换为Object Str...
* 转成json */publicstaticStringbeanToString(Object object){String gsonString=null;if(gson!=null){gsonString=gson.toJson(object);}returngsonString;}/** * 转成bean */publicstatic<T>TstringToBean(String gsonString,Class<T>cls){Tt=null;if(gson!=null){t=gson.fromJson(gsonString,cls);}retu...
* 转成json */publicstaticStringbeanToString(Object object){StringgsonString=null;if(gson !=null) { gsonString = gson.toJson(object); }returngsonString; }/** * 转成bean */publicstatic<T> TstringToBean(String gsonString, Class<T> cls){Tt=null;if(gson !=null) { t = gson.fromJson(...
public static void myJson(Student1 student1) { String str = JSONObject.toJSONString(student); Student2 student2 = JSON.parseObject(str, new TypeReference<Student2>(){}); } 一、提取JsonObject(或Map)中的key-value值 1、获取JsonObject 的key public void myJson(JSONObject params){ Map<String...
今天在尝试用泛型写json解析方法的时候出现了问题,看错误信息就是‘类型’转换问题。调试断点,果然发现这LinkedTreeMap有点不同,如下: 如果代码这样写: publicstatic<T>List<T>jsonToDto(String message,String jsonHead,Tt){//这里是用的TJsonObject jsonObject=newJsonParser().parse(message).getAsJsonObject(...
1、String转换为JSONObject String param = "{\"age\":\"24\",\"name\":\"cool_summer_moon\"}"; JSONObject jsonObject = JSONObject.parseObject(param); Object object = jsonObject.get("name"); 2、JSONObject转换为String String jsonString = jsonObject.toJSONString(); ...
然后,使用Gson对象的toJson()方法将列表转换为JSON字符串。 import com.google.gson.Gson; import java.util.ArrayList; import java.util.List; public class Main { public static void main(String[] args) { // 创建一个包含不同类型对象的列表 List<Object> myList = new ArrayList<>(); myList.add(...
...static final String toJSONString(Object object, boolean prettyFormat); //将JavaBean转换为JSONObject或者JSONArray...的常见使用GSON是Google提供的用来在Java对象和JSON数据之间进行映射的Java类库。...可以将一个Json字符转成一个Java对象,或者将一个Java转化为Json字符串。...("反序列化成List后的...
Can't seem to figure this out. I'm attempting JSON tree manipulation in GSON, but I have a case where I do not know or have a POJO to convert a string into, prior to converting to JsonObject. Is there a way to go directly from a String to JsonObject? I've tried the following ...
二、Java 对象转换为 Json 字符串 将Java 对象转换为 Json 字符串相对来说简单一些,代码如下: Student 类: public class Student { private String id; private String name; @SerializedName("score") private int marks; private List<String> hobbies = new ArrayList<>(); public Student...