longtime=getCurrentTime(); Set<String>entryNames=newHashSet<String>(); for(Map.Entry<String,Set<String>>entry:cache.entrySet()){ StringclassName=entry.getKey(); Classclazz=getClassCacheEntry(className); if(clazz==null)continue; StringentryName=getPath(clazz,localData.precompiledEntries); if(en...
def currentTime = new Date().format("yyyy-MM-dd HH:mm:ss") def urlVisited = "https://www.vipshare.com" def logEntry = [timestamp: currentTime, url: urlVisited] logFile << JsonOutput.toJson(logEntry) << "\n" // 模拟延迟 sleep(5000) monitorNetwork() 此示例中,脚本持续运行,模拟捕...
在JMeter中,我有一个变量,在用户定义的变量中。current_epoch_time = ${__groovy(vars.get("current_time").substring(0\,10))} 然而,我遇到了一堵墙,(1)试图 浏览0提问于2018-02-16得票数 0 1回答 如何获取groovy中的最新时间(而不是日期),并在其中添加10分钟?
尝试使用Joda Time而不是标准的java.util.Date类。Joda时间库有更好的API来处理日期。
假设您指的是您所在时区的午夜，您可以这样做以获得以毫秒为单位的历元：
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at org.eclipse.core.internal.runtime.AdapterManager.getFactories(AdapterManager.java:209) at org.eclipse.core.internal.runtime.AdapterManager.getAdapter(AdapterManager.java:292) at org.eclipse.core.runtime.PlatformObject.getAdapter(PlatformObject.java:68) ...
if (shouldCacheSource) sourceCache.put(codeSource.getName(), answer); return answer; } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 系统每执行一次脚本,都会生成一个脚本的Class对象,这个Class对象的名字由 “script” + System.currentTimeMillis()+Math.abs(text.hashCode()组成,即使...
private Date create_time; private Date update_time; private Integer visible; public String getRule() { return rule; } public void setRule(String rule) { this.rule = rule; } public String getName() { return name; } public void setName(String name) { ...
getRule()); rules.add(groovyDb); } return rules; } } 6.3 数据库访问相关实体 Rules: package cn.pomit.skill.groovy.rule.db; import java.util.Date; public class Rules { private Integer id; private String rule; private String name; private Date create_time; private Date update_time; ...