Interesting Greedy Algorithm By SiddharthBora, 12 years ago, Problem : I give you a number n >= 2. Now you generate all the prime numbers <= n (say p1, p2, p3... pn). Now I ask you to divide the prime numbers into the minimal number of groups such that product of all the ...
Usual algorithm: Dynamic programming (refer to this blog :Codeforces blog) My (maybe-wrong) greedy idea: Root the tree at arbitrary node, let say node 1. Find the distances of other nodes to node 1 (means find the height of each node). Sort the nodes according to their distances to no...
Codeforces 509C Sums of Digits 贪心 摘要:这道题目有人用DFS、有人用DP我觉得还是最简单的贪心解决也是不错的选择。Ok,不废话了,这道题目的意思就是原先存在一个严格递增的Arrary_A,然后Array_A[i] 的每位之和为Array_B[i]现在给你一个Array_B, 让你在条件:Array_A[len] Minimize下求出次数...阅读全...
我们从右往左滑动区间, 假设dp[i]表示i为左端点时的最大长度, 通过观察可以发现, 每添加一个点, 该点dpdp值=它右侧第一个比它大位置处dpdp值+1, 但是每删除一个点会将所有以它为根的dpdp值全-1, 所以可以根据转移建一棵树, 需要有单点查询单点更新以及树链加, 可以用线段树维护dfs序O(logn)O(logn...
C++ #include<iostream> #include<cstring> #include<cmath> #include<algorithm> usingnamespacestd; typedeflonglongll; intmain(){ lln,k,M,D; cin>>n>>k>>M>>D; //is D is small llans=0; for(lli=0;i<D;i++){ llx=n/(i*k+1);// candies people have ...
Petya wrote a quick bug-free code which he believes solves this problem. After that Petya decided to give this problem for April Fools Day contest. Unfortunately, Petya might have made a mistake, and it's quite possible that his algorithm is wrong. But this isn't a good excuse to leave...
algorithmstringspojuvabacktrackingdata-structuresgreedycodeforcesdynamic-programmingproblem-solvingnumber-theorysegment-treedpcsesgraph-the UpdatedMar 14, 2021 C++ souraavv/NPTEL-DAA-Programming-Assignment-Solutions Star40 Code Issues Pull requests Discussions ...
贪心(Greedy Algorithm)11. 盛最多水的容器44. 通配符匹配45. 跳跃游戏 II55. 跳跃游戏122. 买卖股票的最佳时机 II python java leetcode 数组 字符串 原创 firstgtb 2023-05-22 10:35:58 168阅读 ACM Greedy Mouse Greedy Mouse时间限制:1000ms | 内存限制:65535KB难度:3描述AfatmousepreparedMpounds...
The elevator selects the direction of moving by the following algorithm. If the elevator is empty and at the current time no one is waiting for the elevator on any floor, then the elevator remains at the current floor. Otherwise, let's assume that the elevator is on the floor number ...
#include<cstdio> #include<algorithm> #include<queue> #include<cstring> using namespace std; #define N 1000005 #define MOD 998244353 #define INF 0x3f3f3f3f int rd() { int x=0,f=1;char c=getchar(); while(c<'0'||c>'9'){if(c=='-') f=-1; c=getchar();} while(c>='0'...