Can you solve this real interview question? Greatest Common Divisor Traversal - You are given a 0-indexed integer array nums, and you are allowed to traverse between its indices. You can traverse between index i and index j, i != j, if and only if gcd(nu
Github 同步地址: https://github.com/grandyang/leetcode/issues/1071 参考资料: https://leetcode.com/problems/greatest-common-divisor-of-strings/ https://leetcode.com/problems/greatest-common-divisor-of-strings/discuss/307242/C%2B%2B-3-lines https://leetcode.com/problems/greatest-common-divisor-o...
【LeetCode】 1071. Greatest Common Divisor of Strings 字符串的最大公因子(Easy)(JAVA) 题目地址: https://leetcode.com/problems/greatest-common-divisor-of-strings/ 题目描述: For strings S and T, we say “T divides S&r...leetcode 1071. Greatest Common Divisor of Strings 字符串的最大公因子...
例如示例中的str1 ="ABCABC",str2 ="ABC",str1拼接str2后变成"ABCABCABC",str2拼接str1后变成"ABCABCABC"。而str1 ="LEET",str2 ="CODE",str1拼接str2后变成"LEETCODE",str2拼接str1后变成"CODELEET",两者显然不相等,肯定不存在公约数。 那怎么找到他们的最大公约数呢? 思路:借助字符串拆分。用不...
Can you solve this real interview question? Greatest Common Divisor of Strings - For two strings s and t, we say "t divides s" if and only if s = t + t + t + ... + t + t (i.e., t is concatenated with itself one or more times). Given two strings str1 and
[leetcode] 1071. Greatest Common Divisor of Strings Description For two strings s and t, we say “t divides s” if and only if s = t + … + t (t concatenated with itself 1 or more times) Given two strings str1 and str2, return the largest string x such that x divides both ...
【LeetCode】1071. Greatest Common Divisor of Strings 解题报告(Python & C++) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力遍历 日期 题目地址:https://leetcode.com/problems/greatest-common-divisor-of-strings/ 题目描述 For strings S ...
Output: “ABC” Example 2: Input: str1 = “ABABAB”, str2 = “ABAB” Output: “AB” Example 3: Input: str1 = “LEET”, str2 = “CODE” Output: “” Note: 1 <= str1.length <= 1000 1 <= str2.length <= 1000 str1[i] and str2[i] are English uppercase letters. ...
LeetCode 1071. Greatest Common Divisor of Strings字符串的最大公因子【Easy】【Python】【字符串】 Problem LeetCode For stringsSandT, we say "TdividesS" if and only ifS = T + ... + T(Tconcatenated with itself 1 or more times)
LeetCode 1071. Greatest Common Divisor of Strings 1071. Greatest Common Divisor of Strings(字符串的最大公因子) 链接 https://leetcode-cn.com/problems/greatest-common-divisor-of-strings 题目 对于字符串 S 和 T,只有在 S = T + ... + T(T 与自身连接 1 次或多次)时,我们才认定 “T 能除...