Why does the function behave this way? Give reasons for your answers. How does the term \dfrac{1}{4} affect the graph of y = sin \left ( x - \dfrac{1}{4} \right )? Graph the following: y= 3 \sin (2x + \pi/2) Graph the vector fu...
Graph the vector function r(t)= (3 \cos t)i + (3 \sin t)j + (2t)k and then graph r'(t) at \frac{\pi}{4}. Sketch (by points) the graph of 1. r = 2 \sin 3 \theta. \\ 2. r = 2 - 4 \cos \theta. \\ 3. r = 2 + \sin \theta. ...
Use a graphing utility to graph the function. Describe the behavior of the function as x approaches zero. f (x) = sin 1 / x Graph the vector function r(t)= (3 \cos t)i + (3 \sin t)j + (2t)k and then graph r'(t) at \frac{\pi}...
//Vector3 position;varscale =Vector3.one /5f; Using X to Define Y The idea is that the positions of our cubes are defined as⎡⎢⎣xf(x)0⎤⎥⎦[xf(x)0], so we can use them to display a function. At this point the Y coordinates are always zero, which represents the tr...