The graph of the function y = 2x + 1 intersects with a rectangle at points A(1, 3) and B(2, 5). What is the length of the rectangle's side parallel to the x-axis? A. 1 B. 2 C. 3 D. 4 相关知识点: 试题来源: 解析 B。解析:点 A 和点 B 的横坐标分别为 1 和 2,两点...
结果1 题目3 (i) Sketch the graph of y=|(2x+1)(x-2)| for-2≤x≤3 , showing the coordinates of the points where the curve meets the x- and y-axes.[3] 相关知识点: 试题来源: 解析 0 4 2 X 21.510.5 00.511.52 反馈 收藏 ...
百度试题 结果1 题目In exercises, use the graph of y=f(x) to graph each function g.g(x)=-f(2x)-1 相关知识点: 试题来源: 解析反馈 收藏
Finding the x- and y-intercepts may be done either graphically or algebraically. Functions and equations may either be linear or nonlinear. Linear functions are those drawn with a straight line as seen in the illustration below: Graph of y = 2x - 6 with x- and y-intercepts...
the graph of an equation (y = 2x -3) is a straight line. the graph of an inequality (3x -2y < 12) is a area(two intersecting straight lines.) 相关推荐 1What is the difference between the graph of an equation (y = 2x -3) & the graph of an inequality (3x -2y < 12)?反馈...
Use the graph of y = f (x) to graph the function. y = f (x - 1) Graph the function f(x)=8x-7 Graph the function y = -\dfrac{3}{2}\cot 2x. Graph the function f(x) = -x^3 + 4x^2 - x + 3. Graph the function. h(t)=-(t-2)^3+3 ...
View Solution Draw the graph ofy=sin2x. View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium NCERT Solutions for Class 9 English Medium ...
The equation of the line tangent to the graph of f(x)=x2 at x=−1 is ( ).A.y−1=2xB.y+1=−2xC.y=x+2D.y−1=−xE.y+2=x 答案 暂无相关推荐 1The equation of the line tangent to the graph of f(x)=x2 at x=−1 is ( ).A.y−1=2xB.y+1=−2x...
g(x)= 2x-2 D. g(x)= 2x + 3 E. g(x)= 3x-2 相关知识点: 试题来源: 解析 E 正确答案:E 解析:You can see that all five choices are linear functions whose graphs are lines with various slopes and y-intercepts. The graph of Choice A is a line with slope 1 and y-intercept ...
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