百度试题 结果1 题目Find the gradient of the line with equation 2y - 3x = 102y-3x=102y=3x+10or 1.53y=3/2x+5 相关知识点: 试题来源: 解析 or 1.52y-3x=102y=3x+10 反馈 收藏
The gradient (also called slope) of a line tells us how steep it is. To find the gradient: Have a play (drag the points):
百度试题 结果1 题目A line has equation y=6x-1Write down the gradient of the line 6 相关知识点: 试题来源: 解析 6 反馈 收藏
Amir Trs2018년 10월 25일 0 링크 번역 마감:Amir Trs2018년 10월 26일 data.mat Capture.PNG this formul is very bad and i dont know type this for my data in matlab :| I spent 1 day typing this formula :( ...
Write the gradient of the line perpendicular to the line with gradient. (a) 5 (b) 7 (c) -4 (d) -9 Gradient: In mathematics, the gradient is also referred to as the slope. It defines the direction and steepness of a line. The gradient of a line ca...
8 The equation of line L is 2y= 3-x.(a) Find the gradient of line L.Answer(a) ...[2](b) Write down the gradient of a line parallel to L.Answer(b) ...[](c) Find the equation of the line parallel to L that passes through the point (0, 6). 相关知识点: 试题来源...
For each k find the value of λ that minimizes (1.6)f(x(k)−λ∇f(x(k))) This procedure is known as a line-search. The reader will note that this is also a minimization problem. However, since x(k) is known, it is a one-variable minimization problem in the step size λ....
Example 3(a) Draw the graph of the line with equation y=x+1.(b) What is the gradient of the line? 相关知识点: 试题来源: 解析 ITheUbkxhoushen、toculculalctheaMirdinalcsofmwhcpoinl、un(IklineII he fxvinh utih cmwdirwles ( 2K ( 2,IK(>1,0);(0f I X (2t l)iind h(mnr...
Find the gradient of L.(2)Find the coordinates of the point where L crosses the y-axis.(3)Find an equation of the line that is parallel to L and crosses the x-axis at (-2,0) 相关知识点: 试题来源: 解析 (1)1.5(2)(0,-7.5)(3)y=1.5x+3 (1)N/A.(2)N/A.(3)N/A....
For a linear gradient with an initial concentration of jB,0 of the active elution component, the retention time t g,j is given by the equation:选择合适的梯度是困难的,最好根据经验进行优化。对于活性洗脱组分初始浓度为j B,0 的线性梯度,保留时间t g,j 由下式给出: where m is the constant ...