aDistrict 区[translate] a传统的出题模式 The tradition sets the topic of a composition the pattern[translate] agiven by the following equation. 由以下等式给出。[translate]
Given the following equations andΔH°values, determine the heat of reaction(kJ)at298Kfor the reaction:,3C(s)+4H2(g)→C3H8(g) C3H8(g)+5O2(g)→3CO2(g)+4H2O(g),ΔH°(kJmol)=-2055 C(s)+O2(g)→CO2(g),ΔH°(kJm...
Given the following differential equation, which represents the model of a physical system, determine (A)the time constant of the system, (B)the equation for the time response of the system with initial value of0(x0=0) (C)the corresp...
Solve the differential equation ( y)( x)=x+3 with the initial condition y(0)=3, and use your solution to find y(2). 相关知识点: 试题来源: 解析 11 ( y)( x)=x+3 y=(x+3) xy=(x^2)2+3x+Cy(0)=33=(0^2)2+3(0)+CC=3 ⇒ y=(x^2)2+3x+Cy(2)=(2^2)2...
The stiffness of the drive train is infinite and the friction factor and the inertia of the turbine must be combined with those of the generator coupled to the turbine. The output power of the turbine is given by the following equation. 模型根据涡轮的稳定力量特征。 传动的僵硬是无限的,并且...
Given the differential equationx^2(dy)/(dx)=y+xywith boundary condition y= 1 at x= 1:Find a degree 2 Taylor polynomial close to x= 1 to approximate thesolution. 相关知识点: 试题来源: 解析 1+2(x-1)+1/2(x-1)^2 反馈 收藏 ...
结果1 题目 You are given that the equation f(x)=0 has a solution at x=3. Using this information, write down as many solutions as you can to each of the following equations.f( x)=0 相关知识点: 试题来源: 解析 ± 3 反馈 收藏 ...
In evaluating whiteness of light from a light source or a luminaire, whiteness W is given by the following equation, W =−5.3 C +100, wherein chroma C is determined by the CIE 1997 Interim Color Appearance Model (Simple Version).
x2=-|||-a-1-|||-1+21-|||-Since the roots of the original equation-|||-are positive integers,given a-1=1 or a-1=2,-|||-then a=2 or 3.If when a-1=0,that is,a=1,-|||-the solution to the original equation is x 1,-|||-which satisfies the condition.In sum...
Given the equation below. solve for t.+15s/(t-15)=(t+15)/(s+30) OA. t=±√(5-225)OB. t=±(s+15)OC. t=±√(s^2+30s-225)OD. t=±(s^2+225) 相关知识点: 试题来源: 解析 s/(t-15)=(t+15)/(s+30) AnS:CB)