百度试题 结果1 题目Divide using synthetic division. Give the quotient and the remainder.(3x^3-4x^2+x-16)÷ (x-2)Quotient: ___Remainder: ___ 相关知识点: 试题来源: 解析 3x^2+2x+5 -6 反馈 收藏
aIf you were to use the integer quotient and remainder, a division by zero results in a quotient of zero. 如果您将使用整数商数和剩下的人,一个被零除结果在商数零。[translate] a但我坚信会很快的融进这个社会 But I believed can very quick melt this society[translate] ...
题目 An even number x divided by 7 give some quotient plus a remainder of 6. Which of the following, when added to x, gives a sum which must be divisible by 14 ?() A.1 B.3 C.7 D.8 E.13 相关知识点: 试题来源: 解析 D [解析] 设x被7除时的商值为m,其中m为整数,则根据题...
modulus = (num/den - quotient) * den with the same result. 2 Comments Guillaume on 17 Mar 2020 Or, rather than misinterpreting the mod function, the OP doesn't understand the word 'remainder' "However 23/5 is 4.6, 4 with a remainder 6 ...
aIf you divide 14 by 3, the quotient is 4 with a remainder of 2. 如果您除14 3,商数是4以剩下的人2。[translate] aI'm still chinese 我仍然是汉语[translate] athe processing complex has been on the market since the late 1990s 处理复合体在市场上从90年代后期[translate] ...
1【题目】Given a two-digit number, if itis divided by the digitin its ones place, the quotient is 9 andthe remainder is 6. If it is divided by the sum of the digitsin the ones place and in the tensplace, the quotient is 5 and the remainder is 3. Find this two-digit number...
fprintf('\n%%Quotient:\n'); disp(q); fprintf('\n%%Remainder:\n'); disp(rem); fprintf('\n%%Check:\ngf9.sub(a,gf9.conv(q,b)) %%should be equal to rem'); gf9.sub(a,gf9.conv(q,b)) %%%% % Eg. 4 % output the primitive polynomial ...
modulus = (num/den - quotient) * den with the same result. 2 Comments Guillaume on 17 Mar 2020 Or, rather than misinterpreting the mod function, the OP doesn't understand the word 'remainder' "However 23/5 is 4.6, 4 with a remainder 6 ...
modulus = (num/den - quotient) * den with the same result. 2 Comments Guillaume on 17 Mar 2020 Or, rather than misinterpreting the mod function, the OP doesn't understand the word 'remainder' "However 23/5 is 4.6, 4 with a remainder 6 ...