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解:如图3, EG平分∠AEH,EH平分∠GEF,FH平分∠CFG,FG平分∠HFE, ∴∠AEG=∠GEH=∠HEF=1/3∠AFE ,∠CFH=∠HFG=∠EFG=1/3∠CFE , 由(1) 可知, ∠G =∠AEG+∠CFG,∠H =∠AEH+∠CFH, ∴∠G=1/3∠AEF+2/3∠CFE=95° , ∵AB∥CD , ∴∠AEF+∠CFE=180° , ∴1/3(∠AEF+∠CFE...
发表了博文《FHFGFGHFCDGJHDGHCFGHFCJHFGVC》SABSABSABSABSABSABSABSABSABSABSABSABSABSABSABSABSABSABSABSABSABSAhttp://t.cn/RhVKbzJ
(3)解: ∵EG 平分∠AEH,EH平分∠GEF,FH平分∠CFG FG平分∠HFE, ∴∠AEG=∠GEH=∠HEF=1/3∠AEF 、∠CFH=∠HFG=∠EFG=1/3∠CFE , 由(1),可知∠G =∠AEG +∠CFG,∠H =∠AEH +∠CFH, ∴∠G=1/3∠AEF+2/3∠CFE=95° , ∴1/3(∠AEF+∠CFE)+1/3∠CFE=95° . ∵AB∥CD , ...