Part 1: What is iPhone UDID? Is It Important? Part 2: So, How to Find iPhone UDID? Method 1: One-Click to Find iPhone UDID without iTunes[FREE]HOT Method 2: Get UDID of iPhone with iTunes Method 3: Get UDID of iPhone with Finder FAQS about iPhone UDID Part 1: What is iPhone ...
获取iOS-UDID iPhone和iPad的UDID无法再使用应用程序检索。 相反,我们可以使用网页和PHP安装配置文件。 结果将通过电子邮件发送给您。 您需要对文件进行编辑以插入您的Web域名。 进行以下编辑: enroll.mobileconfig第8行 done.php 75行 Submit.php第3行点赞(0) 踩踩(0) 反馈 所需:15 积分 电信网络下载 ...
xml"), sb.toString().indexOf("</plist>")+8); //content就是接收到的xml字符串 //进行xml解析即可 String udid = response.setStatus(301); //301之后iOS设备会自动打开safari浏览器 response.setHeader("Location", "http://192.168.1.106:8080/udid.jsp?UDID="+udid); //http:...
不想折腾,想省事的朋友可以考虑UDID定制。 如有需要定制证书可以购买站长合作的店铺 签名失败常见报错解决: 第一种情况,提示,证书申请失败! (将鼠标移动至红色字体的位置。后面会出现一串这样的英文提示。) get +XcodeToken+err+SRP_Setp1+err:hsc=200+ec=-20101+au=+em=Your+account+information+was+entered+in...
为分界线#defineURL_POST1 @"http://ipad-bjwb.bjd.com.cn/DigitalPublication/publish/Handler/APINewsList.ashx"#defineURL_POST2 @"date=20131129&startRecord=1&len=5&udid=1234567890&terminalType=Iphone&cid=213" GET同步 #pragmamark ---GET同步---(void)getTong{// 1 创建URL对象NSURL*url=[NSURL...
[HttpMethod getDataByURLString:@"http://ipad-bjwb.bjd.com.cn/DigitalPublication/publish/Handler/APINewsList.ashx" HttpMethod:@"POST" BodyString:@"date=20131129&startRecord=1&len=30&udid=1234567890&terminalType=Iphone&cid=213" DataBlock:^(id data) { ...
为分界线#defineURL_POST1 @"http://ipad-bjwb.bjd.com.cn/DigitalPublication/publish/Handler/APINewsList.ashx"#defineURL_POST2 @"date=20131129&startRecord=1&len=5&udid=1234567890&terminalType=Iphone&cid=213" GET同步 #pragmamark ---GET同步---(void)getTong{// 1 创建URL对象NSURL*url = [NS...
iPhone 15 Pro 17.4 Donor PostedSeptember 8, 2024(edited) Hello! If you currently have an active subscription to app+ then you may be able to transfer yourudid. If you do not currently have a subscription then unfortunately app+ is sold out right now and you’ll need to wait until it ...
[NSURLURLWithString:urlString];//创建POST请求参数,为NSData类型NSString*postString =@"date=20151031&startRecord=1&len=5&udid=1234567890&terminalType=Iphone&cid=213";//将string类型转换为NSData类型NSData*postParameterData = [postString dataUsingEncoding:NSUTF8StringEncoding];//创建请求,因为NSURL...
Apple has deliberately disallowed apps from accessing any persistent device identifier such as the UDID or serial number, for privacy reasons. They don’t want apps tracking individual users. So there is no such API. 0 Copy junkpile answer ...