[ALL | DISTINCT | DISTINCTROW ] [HIGH_PRIORITY] [STRAIGHT_JOIN] [SQL_SMALL_RESULT] [SQL_BIG_RESULT] [SQL_BUFFER_RESULT] [SQL_CACHE | SQL_NO_CACHE] [SQL_CALC_FOUND_ROWS] select_expr [, select_expr] ... [into_option] [FROM table_references [PARTITION partition_list]] [WHERE where_...
}else{if($traverse = $query->getTraverse()) {//Build the traverse string here$text =$this->sqlTraverseToString($traverse); }else{ $text =$this->sqlSelectToString($query->getSelect(), $query->getDistinct()); } }if($query->getFrom()) { $text .=$this->sqlFromToString($query->ge...
SQL_AF_DISTINCTSQL_AF_MAXSQL_AF_MINSQL_AF_SUMSQL-92 入門層級一致性驅動程式一律會傳回所有支持的選項。 SQL_ALTER_DOMAIN 3.0 SQLUINTEGER 位掩碼,列舉 ALTER DOMAIN 語句中的 子句,如數據源支援的 SQL-92 中所定義。 SQL-92 完整層級相容驅動程式一律會傳回所有位掩碼。 傳回值 「0」 表示 不支援 ...
SQL_AF_DISTINCTSQL_AF_MAXSQL_AF_MINSQL_AF_SUMSQL-92 入門層級一致性驅動程式一律會傳回所有支持的選項。 SQL_ALTER_DOMAIN 3.0 SQLUINTEGER 位掩碼,列舉 ALTER DOMAIN 語句中的 子句,如數據源支援的 SQL-92 中所定義。 SQL-92 完整層級相容驅動程式一律會傳回所有位掩碼。 傳回值 「0」 表示 不支援 ...
I need to get results DISTINCT by short_name - PostgreSQL supports this. In SQL the query looks like: SELECT DISTINCTON(short_name) short_name, id, full_nameFROMmaterials; DISTINCT clause should go first. When I try to get rows like ...
SQL_AF_DISTINCTSQL_AF_MAXSQL_AF_MINSQL_AF_SUMA SQL-92 Entry level-conformant driver will always return all of these options as supported. SQL_ALTER_DOMAIN 3.0 An SQLUINTEGER bitmask enumerating the clauses in the ALTER DOMAIN statement, as defined in SQL-92, supported by the data source....
I have a DataTable that has several hundred rows. I want to get a row count of distinct values in a particular column. For example, I have a DataTable of Product Orders, but I want to get the number of unique Customers. I was using this code, but I can't rely on it because my...
Get DISTINCT records using DataTable.Compute Method Get distinct rows from a DataView? Get Domain Name from Active directory Get each pixel color in an image? Get Enum By Index Get Enum from assembly with reflection Get enum values based on attribute Get field names from Binding Source Get...
INNER JOIN SECOND_TABLE as ST ON ST.Question_ID=FT.Question_ID Where Userid=@userID so as my Second_Table has two rows for Question one it shows two result set due to inner join I have checked left , right all joins FOR QUESTION_ID=1 I have Two Recrods in the Second Table so...
SQL 是声明式语言,即对用户来说,只关心它能做什么,不用关心它怎么做。这样可能会产生潜在的性能问题:排序,会产生排序的代表性运算有下面这些 GROUP BY 子句 ORDER BY 子句 聚合函数(SUM、COUNT、AVG、MAX、MIN) DISTINCT 集合运算符(UNION、INTERSECT、EXCEPT) ...