1publicclassSubarrayWithGivenSum {2publicstaticint[] findSubarrayWithGivenSum(int[] arr,intsum) {3int[] range =newint[2];4range[0] = -1; range[1] = -1;5if(arr ==null|| arr.length == 0 || sum < 0) {6returnrange;7}8intstart = 0;9intcurrSum = arr[0];10for(intend = ...
Count Subarrays with given sum Count Subarrays with given XOR 07-Two Pointer Technique Check for Pair Sum in Sorted Triplets in Sorted Triplets in Unsorted Print All Pairs with given sum Closest Pair Count Pairs in Sorted Subarray with given sum Count distinct elements in every window of size...
subarrayWithGivenSum.cpp subsetSumProblem.cpp subsetSumProblem2.cpp subsets.cpp swapAllOddAndEvenBits.cpp swappingPairsMakeSumEqual.cpp symmetricTree.cpp theNthFibonnaci.cpp topViewOfBinaryTree.cpp topologicalSort.cpp towerOfHanoi.cpp transitiveClosureOfAGraph.cpp transposeOfAMatrix.cpp...
[GeeksForGeeks] Find subarray with given sum 摘要:Given an unsorted array of nonnegative integers, find a continous subarray which adds to a given number. Examples: There may be more than one subarray 阅读全文 posted @ 2017-10-03 04:02Review->Improve 阅读...
if(end < begin){ // If there are no elements in this subarray return 0; } if(begin == end){ // If there is one element in this subarray return freq[begin]; } // 每往下走一步,都要加上从begin到end的freq和 int fsum = sum(freq, begin, end); // Get sum of freq[i], freq...
Given a binary tree, you need to check whether sum of all covered elements is equal to sum of all uncovered elements or not. In a binary tree, a node is called Uncovered if it appears either on left boundary or right boundary. Rest of the nodes are called covered. ...