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1importjava.util.ArrayList;2importjava.util.Arrays;34publicclassCountWaysOfScore {5privateintways = 0;6privateArrayList<ArrayList<Integer>>results;7publicintgetWaysofScore(int[] points,intscore) {8results =newArrayList<ArrayList<Integer>>();9if(score > 0 && (points ==null|| points.length == ...
2. The LIS problem can be solved using recursion or dynamic programming. 1importjava.util.ArrayList;2importjava.util.Arrays;3importjava.util.Comparator;45classPair {6intfirst;7intsecond;8Pair(intfirst,intsecond) {9this.first =first;10this.second =second;11}12voiddisplay() {13System.out.prin...
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import java.util.Arrays; public class WordWrap { public static void main(String[] args) { int[] l = {3, 2, 2, 5}; int n = l.length; int M = 6; solveWordWrap(l, n, M); } // l[] represents lengths of different words in input sequence. For example, ...
package DP; import java.util.Arrays; // 最长递增子序列-Longest Increasing Subsequence /** Let arr[0..n-1] be the input array and L(i) be the length of the LIS till index i such that arr[i] is part of LIS and arr[i] is the last element in LIS ...
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