那我们就说这个循环的时间复杂度是O(loglogn) //Here c is a constant greater than 1for(inti =2; i <=n; i =pow(i, c)) {//some O(1) expressions}//Here fun is sqrt or cuberoot or any other constant rootfor(inti = n; i >0; i =fun(i)) {//some O(1) expressions} 如何求...
http://www.geeksforgeeks.org/analysis-of-algorithms-set-2-asymptotic-analysis/ 翻译: Rui
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