学习GDScript 应用程序 接下来的步骤在我们的免费开源应用程序Learn GDScript From Zero中进行。 这是一款受 FreeCodeCamp 和 Codecademy 启发的应用程序,但专为 Godot 的 GDScript 编程语言制作。 汉化版: 链接:https://pan.baidu.com/s/1XpeQPvj00UZ_Y9MhFDilXA?pwd=t0a3 提取码:t0a3 这个版本使用了官方的...
This Free and Open-Source app will help you learn Godot's GDScript programming language, even if you're starting from zero.
刘明解 godot 1 这个是用的官方还没有正式版用的汉化文件 一个兄弟帮助我完成了这个版本 jln11 动画特效 5 谢谢分享,一直想找这个的汉化版 登录百度帐号 下次自动登录 忘记密码? 扫二维码下载贴吧客户端 下载贴吧APP看高清直播、视频! 贴吧页面意见反馈 违规贴吧举报反馈通道 贴吧违规信息处理公示1...
我个人比较推荐你的是Learn to Code From Zero with Godot3和Godot Node Essentials两系列课程进行入门。
This app is the free part of a larger paid course to become a game developer: Learn to Code From Zero, with Godot. The series is compatible with Godot 4. How to run the app You can run the app online here: https://gdquest.github.io/learn-gdscript/ Also, you can download the app...
(比如1==1.0为true),但其他情况下可能会导致运行时的错误,如果不确定操作数的类型,使用is_same(a, b)更安全(该函数对值和引用的判断逻辑不同,值类型只要值相等即可,而引用类型比如数组,只能用于判断是否是同一个引用,而不能用于判断两个数组的元素是否等同),比较浮点数可以使用is_equal_approx()和is_zero_...
Learn Godot's GDScript programming language from zero, right in your browser, for free. education app html5 game-development godot gdscript hacktoberfest Updated Dec 23, 2024 GDScript gdquest-demos / godot-open-rpg Star 2.2k Code Issues Pull requests Learn to create turn-based combat wit...
Remove elements from the back of the array Whenever you add or remove an element at a given position within an array, Godot has to resize the array and move all its elements. The cost of this operation is proportional to the number of entries in the array. When the removed element is ...
Whenget_counteris initialized, the value forcountis set to zero, and the value of the return value is set to the inner anonymous function. Calling theget_counterfunction causes the inner function to run to obtain the return value, and this has access to the outer functions' scope. So it ...
var input_dir = Vector2.ZERO ifInput.is_action_pressed("ui_left"): input_dir.x -=1 ifInput.is_action_pressed("ui_right"): input_dir.x +=1 ifInput.is_action_pressed("ui_up"): input_dir.y -=1 ifInput.is_action_pressed("ui_down"): ...