GCF of 14 and 42 is the largest possible number which divides 14 and 42 without leaving any remainder. The methods to compute the GCF of 14, 42 are explained here.
# for GCF ajdMat is a (N+M) by (N+M) mat # lap_matrix L = D^-1(A)D^-1 # 拉普拉斯矩阵 x = torch.sparse.mm(lap_matrix, features) # inter_part1 = self.linear(features + x) inter_feature = torch.mul(x, features) inter_part2 = self.interActTransform(inter_feature) return...
(party7) to MPTY – attempt fails BM-5.3.11 42.4 Multi Party - Clear one party from MPTY, and add MTC to MPTY BM-5.3.12 42.4 Multi Party - Private communication with one party, rest of MPTY on hold BM-5.4.1 42.6.5 USSD - Invoke a USSD request For GPRS network dependent Field ...
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