publicstaticintEuclid(intm,intn){if((m==0&&n==0)||(m<0)||(n<0)){return0;}while(n!=0){intr=m%n;m=n;n=r;}returnm;} (recursion version) publicstaticintEuclidRec(intm,intn){if((m==0&&n==0)||(m<0)||(n<0)){return0;}returnprocess(m,n);}privatestaticin...
天真的方法来计算gcd 使用递归: # Python code to demonstrate naive# method to computegcd( recursion )defhcfnaive(a,b):if(b==0):returnaelse:returnhcfnaive(b,a%b) a =60b=48# prints 12print("Thegcdof 60 and 48 is:",end="")print(hcfnaive(60,48)) 输出: Thegcdof 60 and 48 is:...
最高公因数(HCF),也称为 gcd,可以在 python 中使用数学模块提供的单个函数来计算,因此可以在许多情况下使任务变得更容易。计算gcd 的简单方法 *Using Recursion:```py # Python code to demonstrate naive # method to compute gcd ( recursion ) def hcfnaive(a,b): if(b==0): return a else: return...
# Python code to demonstrate naive# method to compute gcd ( recursion )defhcf(a,b):if(b==0):returnaelse:returnhcf(b,a%b)a=60b=48# prints 12print("The gcd of 60 and 48 is : ",end="")print(hcf(60,48)) 输出 The gcd of60and48is:12 ...
// Rust program to calculate // the GCD using recursion fn calculateGCD(a:i32, b:i32)->i32 { while (a != b) { if (a > b) { return calculateGCD(a - b, b); } else { return calculateGCD(a, b - a); } } return a; } fn main() { let a:i32=45; let b:i32=75; ...
如果您想继续使用递归,这会使事情变得更快,因为随机实例并不是在每个递归步骤上创建的(否则,while循环...
I convert it to non recursive form to save memory and recursion calls. Here is my C++ implementation for my longnum lib, added some rems for lines that are different from standard operators/functions longnum gcd(longnum x,longnum y) { x.sig=+1; x.integer(); // x=abs(int(x)) y...
import java.util.Scanner; public class RecursionDemo { public static void main (String[] args) { Scanner userInput = new Scanner(System.in); System.out.println(& 浏览2提问于2014-03-23得票数 2 回答已采纳 1回答 用欧几里德算法求两个数的GCD? 我试图用欧几里德算法计算两个数字的GCD。我在...
Without recursion: int result = numbers[0]; for(int i = 1; i < numbers.length; i++){ result = gcd(result, numbers[i]); } return result; For very large arrays, it might be faster to use the fork-join pattern, where you split your array and calculate gcds in parallel. Here is...
GCD of two numbers using Recursion Let's consider a program to find the GCD of two numbers in C using Recursion. Recursion.c #include <stdio.h> #include <conio.h> intGCD_Rec(intnum1,intnum2); intmain() { intnum1, num2;