println("Gcd of two numbers is="+g.greater(n1,n2)); else System.out.println("Values should be greater than 0 otherwise gcd is 0"); } } Output: 1 2 3 4 5 Enter first number 5 Enter second number 10 Gcd of two numbers is=5 Using Recursion 1) In this program greater(long a,...
GCD and LCM of two numbers in Java C++ Program to Find GCD of Two Numbers Using Recursive Euclid Algorithm Swift program to find the GCD of two given numbers using recursion Haskell Program to find the GCD of two given numbers using recursion Find out the GCD of two numbers using while lo...
The latter case is the base case of our Java program to find the GCD of two numbers using recursion. You can also calculate the greatest common divisor in Java without using recursion but that would not be as easy as the recursive version, but still a good exercise from the coding intervi...
} Output: The GCD of 45 and 75 is 15. Explanation: In the above program, we created two functionscalculateGCD()andmain(). ThecalculateGCD()function is a recursive function, which is used to calculate the GCD of two numbers and return the result to the calling function. In themain()fun...
Using Recursion Using gcd() and lcm() Functions Using __gcd() Function Using Iteration In this approach, we have used an iterative approach to find the gcd and lcm of n numbers. The gcd function calculates the gcd of two numbers. It runs till 'b' becomes 0 and keeps updating 'a' wi...
Recursion package org.example; import java.util.Scanner;publicclassMain {publicstaticvoidmain(String[] args) { Scanner scanner=newScanner(System.in);intm =scanner.nextInt();intn =scanner.nextInt(); System.out.println(gcd(m, n));
Learn how to calculate the gcd of two numbers in Python using function. Explore step-by-step examples and efficient methods for finding the greatest common divisor.
基本算法：设a=qb+r，其中a，b，q，r都是整数，则gcd(a,b)=gcd(b,r)，即gcd(a,b)=gcd(b,...
I test two c++ program: #include<stdio.h>#include<stdlib.h>typedefunsignedlonglongull;ull nzd(ull a,ull b){if(b==0)returna;a%=b;returnnzd(b,a);}ull n,m;intmain(){scanf("%llu %llu",&n,&m);printf("%llu\n",nzd(n,m));} ...
// Rust program to calculate// the GCD using recursionfncalculateGCD(a:i32, b:i32)->i32{while(a!=b) {if(a>b) {returncalculateGCD(a-b, b); }else{returncalculateGCD(a, b-a); } }returna; }fnmain() {leta:i32=45;letb:i32=75;letres=calculateGCD(a, b); ...