# Define a function to calculate the greatest common divisor (GCD) of two numbers.defgcd(x,y):# Initialize gcd to 1.gcd=1# Check if y is a divisor of x (x is divisible by y).ifx%y==0:returny# Iterate from half o
Program to find GCD/HCF of two numbers using recursion in Kotlin packagecom.includehelp.basicimport java.util.*//function calculate HCF using RecursionfunfindHCF(num1: Int,num2: Int):Int{returnif(num2!=0) findHCF(num2,num1%num2)elsenum1 }//Main Function entry Point of Programfunmain...
Find the GCD of two numbers AIM: To write a program to find the GCD of two numbers using function. Equipments Required: Hardware – PCs Anaconda – Python 3.7 Installation / Moodle-Code Runner ALGORITHM: Define a function. Get the two numbers from the user. Compare the two values, to fin...
Learn how to find the GCD of two numbers in Python using 5 different methods including loops, recursion, math module, and more. Step-by-step examples inside.
Source Code: Using Loops # Python program to find H.C.F of two numbers# define a functiondefcompute_hcf(x, y):# choose the smaller numberifx > y: smaller = yelse: smaller = xforiinrange(1, smaller+1):if((x % i ==0)and(y % i ==0)): ...
the greatest common divisor of two numbers. * * @tparam T The type of the numbers,...
The GCD of 45 and 75 is 15. Explanation: In the above program, we created two functionscalculateGCD()andmain(). ThecalculateGCD()function is a recursive function, which is used to calculate the GCD of two numbers and return the result to the calling function. ...
Ifaandbare single numbers, it gives the highest common factor of those two. If they are arrays, it calculates the highest common factor for each pair of numbers in the arrays. Examples of numpy.gcd in Python Let’s gain a better understanding of numpy.gcd function with a bunch of examples...
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// C++ program to find GCD/HCF of 2 numbers #include <iostream> usingnamespacestd; // Recursive function to find GCD/HCF of 2 numbers intcalculateGCD(intnum1,intnum2) { if(num2==0) { returnnum1; } else { returncalculateGCD(num2, num1%num2); ...