1) In this program we have a function long greater(long a, long b), it calculates the GCD of two numbers a,b and returns the number. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 import java.util.Scanner; class GcdCalcu...
Example 1: Java Program to find GCD of two numbers using for loop In this example, we are finding the GCD of two given numbers usingfor loop. We are running a for loop from 1 to the smaller number and inside loop we are dividing both the numbers with the loop counter “i” which r...
Program to find GCD/HCF of two numbers using recursion in Kotlin packagecom.includehelp.basicimport java.util.*//function calculate HCF using RecursionfunfindHCF(num1: Int,num2: Int):Int{returnif(num2!=0) findHCF(num2,num1%num2)elsenum1 }//Main Function entry Point of Programfunmain...
must support comparison and modulo operations. * @param a First number * @param b Second numb...
Java多线程编程五(线程间通信之ThreadLocal) ThreadLocal 方法 get() 类ThreadLocal解决的是变量在不同线程间的隔离性,也就是不同线程拥有自己的值,不同线程中的值是可以放入ThreadLocal类中进行保存的。 解决get()返回null InheritableThreadLocal的使用(值继承) 继承值再修改 本文主要讲述如何解决非线程安全问题,...
of a given set of numbers. One of the quickest ways to find the LCM of two numbers is to use the prime factorization of each number and then the product of the highest powers of the common prime factors will be the LCM of those numbers. Let us learnhow to find the lowest common ...
// C program to find the GCD// (Greatest Common Divisor) of two integers#include <stdio.h>intmain() {intnum1=0;intnum2=0;intrem=0;intX=0;intY=0; printf("Enter Number1: "); scanf("%d",&num1); printf("Enter Number2: "); scanf("%d",&num2);if(num1>num2) { X=num1;...
The first line of input is an integer T(T<=100) representing the number of test cases. The following T lines each contains two numbers N and M (2<=N<=1000000000, 1<=M<=N), representing a test case. Output For each test case,output the answer on a single line. Sample Input 3 ...
* {@code gcd(x, 0)} is the absolute value of {@code x}, except * for the special cases above. * The invocation {@code gcd(0, 0)} is the only one which returns * {@code 0}. * * * @param p Number. * @param q Number. * @...
greatest common number which can divide all the given numbers. The lcm refers to the 'Least Common Multiple' i.e. the lowest common multiple of all the numbers. To find the gcd and lcm of n numbers in C++, we can use various approaches like iterative approach, or built-in C++ ...