(https://leetcode-cn.com/problems/greatest-common-divisor-of-strings/solution/zi-fu-chuan-de-zui-da-gong-yin-zi-by-leetcode-solu/有详细的说明) AC代码: classSolution {public:stringgcdOfStrings(stringstr1,stringstr2) {if(str1 + str2 != str2 + str1)return"";returnstr1.substr(0, __...
He wants to compress a into an array b of size n−1. To do this, he first discards exactly 2 (any two) elements from a. He then perfor...__gcd() 在翻别人的题解的时候偶然发现了这个函数,然后就去查了查,但是相关内容不多,__gcd(x,y);好像是GNU的内部函数,不是一个标准库里的函数...
学习leetcode_365: Water and Jug Problem的解法:辗转相除相关内容(最大公约数、裴蜀定理、欧几里得算法和扩展欧几里得算法)。 正文: 1、问题描述 You are given two jugs with capacitiesxandylitres. There is an infinite amount of water supply available. You need to determine whether it is possible to m...
对于Scanner的进一步理解还是在LeetCode的一道算法题上,题目大意是输入一组分式加法构成的字符串,要求输出分式相加的结果。首先是输入”-2/3+2/3-4/5″,接着求其和。...首先第一步需要解析字符串为所需的数据,我使用了split()的方式,有位大哥就使用了`scanner.useDelimiter(pattern)`方法,直接将数据解析到了Sc...
//https://leetcode.com/problems/maximize-score-after-n-operations/discuss/1200095/Java-Backtrack-with-memoizationclassSolution {intres;intn; HashMap<String, Integer>memo;publicintmaxScore(int[] nums) { res= 0; n= nums.length/2; memo=newHashMap<>();returnbacktrack(nums, 1,newHashSet<>(...
//https://leetcode.com/problems/maximize-score-after-n-operations/discuss/1200095/Java-Backtrack-with-memoizationclassSolution {intres;intn; HashMap<String, Integer>memo;publicintmaxScore(int[] nums) { res= 0; n= nums.length/2; memo=newHashMap<>();returnbacktrack(nums, 1,newHashSet<>(...
http://www.martinkysel.com/hackerrank-sherlock-and-gcd-solution/ #http://www.martinkysel.com/hackerrank-sherlock-and-gcd-solution/#fromfunctoolsimportreducedefgcd(a, b):ifa == 1orb == 1:return1ifa % b ==0:returnbreturngcd(b, a %b)defmultiple_gcd(arr):returnreduce(lambdax,y: gcd...
output AI检测代码解析 1 1. input AI检测代码解析 61803398874989484820458683436563811772030917980576 61803398874989484820458683436563811772030917980576 1. output AI检测代码解析 61803398874989484820458683436563811772030917980576 1. AI检测代码解析 #include<iostream> #include<string.h> ...
#include<string.h> #include<stdlib.h> #include<math.h> #include<vector> #include<queue> #include<stack> #include<map> #define N 101000 using namespace std; vector<int>q[N]; int num[N]; int a,b,c,d,k; void init(){ for(int i=0;i<=N;i++){ ...