You are given an array After processing each query you need to output the greatest common divisor (GCD) of all elements of the array a. Since the answer can be too large, you are asked to output it modulo 10^9+7. Input The first line contains two integers — n and q (1≤n,q≤...
然后区间查询最小值来获取这个质因子目前的贡献vv 然后再开一个prepre数组用于记录每个质因子最小幂次的前置状态 由于我们不能每次都算一遍每个质因子的贡献,所以只能尝试去维护答案变量ansans 所以每次我们可以得到质因子tt所作出贡献的幂次差值为v−pre[d]v−pre[d] 故在当前点修改之后,需要将当前贡献加入答...
You are given an array aa of length nn. You are asked to process qq queries of the following format: given integers ii and xx, multiply aiai by xx. After processing each query you need to output the greatest common divisor (GCD) of all elements of the array aa. Since the answer can...
}voidpushup(intu){ tr[u].mi=min(tr[tr[u].l].mi,tr[tr[u].r].mi); }voidmodify(int&u,intl,intr,intx,intk){if(!u) u=++idx;if(l==r){ tr[u].mi+=k;return; }intmid=l+r>>1;if(x<=mid) modify(tr[u].l,l,mid,x,k);elsemodify(tr[u].r,mid+1,r,x,k); pushu...
D. GCD of an Array 数据结构 + 思维 题目大意: 给你一个大小为 n 的序列,有 q 次操作,每次操作将 \(a_i\) 乘以 \(x\) ,在每次操作之后输出整个序列的 \(gcd\) 题解: 首先明确要对每一个数进行质因数分解,对质数分开讨论 然后分解完之后,用map存下来,很简单的想法,就是map存下来之后,然后还要...
D. GCD of an Array(mutiset维护gcd),ps:这题主要是对stl中mutiset的使用要熟悉AC代码:#include<bits/stdc++.h>
Modified GCD of Order K for an array is the Maximum number that divides at leastceil(n/k) number of elements of the array.For example Modified Gcd of Order 2 for array A is the Maximum number that divides at least half of its elements. For example-given n=10, k=3 and array A={...
Can you solve this real interview question? GCD Sort of an Array - You are given an integer array nums, and you can perform the following operation any number of times on nums: * Swap the positions of two elements nums[i] and nums[j] if gcd(nums[i], nu
Maintain an array a with index from to . There are two kinds of operations: Add to for every that . Query 插入操作: 2.查询操作: #include<bits/stdc++.h> #define me(a,x) memset(a,x,sizeof(a)) #define IN freopen("in.txt","r",stdin); ...
Firstly, array lidar is used to acquire the armor target data. Secondly, the armor target data is expanded with an improved GAN(Generative Adversarial Network) to increase the diversity of training data. Afterward, the expanded dataset is fed into the GCD-YOLv5(You Only Look Once) for ...