,an (1≤ai≤2⋅10^5)— the elements of the array aa before the changes. The next q lines contain queries in the following format: each line contains two integers i and x (1≤i≤n, 1≤x≤2⋅10^5). Output Print q lines: after processing each query output the GCD of all elem...
D. GCD of an Array 数据结构 + 思维 题目大意: 给你一个大小为 n 的序列,有 q 次操作,每次操作将 \(a_i\) 乘以 \(x\) ,在每次操作之后输出整个序列的 \(gcd\) 题解: 首先明确要对每一个数进行质因数分解,对质数分开讨论 然后分解完之后,用map存下来,很简单的想法,就是map存下来之后,然后还要...
D. GCD of an Array 数据结构 + 思维 题目大意: 给你一个大小为 n 的序列,有 q 次操作,每次操作将 aiai 乘以xx ,在每次操作之后输出整个序列的 gcdgcd 题解: 首先明确要对每一个数进行质因数分解,对质数分开讨论 然后分解完之后,用map存下来,很简单的想法,就是map存下来之后,然后还要放到一个数据结构...
}voidpushup(intu){ tr[u].mi=min(tr[tr[u].l].mi,tr[tr[u].r].mi); }voidmodify(int&u,intl,intr,intx,intk){if(!u) u=++idx;if(l==r){ tr[u].mi+=k;return; }intmid=l+r>>1;if(x<=mid) modify(tr[u].l,l,mid,x,k);elsemodify(tr[u].r,mid+1,r,x,k); pushu...
GCD of an Array 传送门 题目大意 你会得到一个数组a,并且会有q个查询,给定两个数字i和x,将a[i]乘以x,输出每次查询后的数组a的gcd 题解 牛客的寒假训练营有一道比这个简单的同类型题,这里上个牛客的传送门,我们先考虑如果数组a没有被修改,应该怎么求他们的gcd,很显然,我们可以将每个数字进行质因子分解,...
Codeforces Round #705 (Div.2) D - GCD of an Array 题意 给定长度为\(n\)的数组\(\{a\}\),有\(q\)次操作与询问 每次操作给定\(i\)与\(x\),使得\(a_i=a_i*x\) 每次操作后询问此时这个数组所有元素的最大公因数GCD是多少 限制
You are given an array aa of length nn. You are asked to process qq queries of the following format: given integers ii and xx, multiply aiai by xx. After processing each query you need to output the greatest common divisor (GCD) of all elements of the array aa. Since the answer can...
Can you solve this real interview question? GCD Sort of an Array - You are given an integer array nums, and you can perform the following operation any number of times on nums: * Swap the positions of two elements nums[i] and nums[j] if gcd(nums[i], nu
Codeforces1493D GCD of an Array 題目連結 點我跳轉 題目大意 給定一個長度為\(N\)的序列\(A\) 有\(Q\)次操作,每次操作給定兩個數\(i\),\(X\),使得\(A[i] = A[i] \times X\) 問每次操作後整個序列的\(gcd\)為多少 (對\(1e9+7\)取模)...
Maintain an array a with index from to . There are two kinds of operations: Add to for every that . Query 插入操作: 2.查询操作: #include<bits/stdc++.h> #define me(a,x) memset(a,x,sizeof(a)) #define IN freopen("in.txt","r",stdin); ...