2018-03-14 11:06:53.186840+0800 GCDDemo1[1945:82494] 1—<NSThread: 0x604000072f00>{number = 1, name = main} 2018-03-14 11:06:55.187418+0800 GCDDemo1[1945:82494] 2—<NSThread: 0x604000072f00>{number = 1, name = main} 2018-03-14 11:06:57.188837+0800 GCDDemo1[1945:82494] 2...
输出结果:2018-02-23 20:36:41.769269+0800 YSC-GCD-demo[19929:5005237] currentThread---<NSThread: 0x604000062d80>{number = 1, name =main}2018-02-23 20:36:41.769496+0800 YSC-GCD-demo[19929:5005237] asyncConcurrent---begin2018-02-23 20:36:41.769725+0800 YSC-GCD-demo[19929:5005237] asyncC...
This is why: The gcd(a,d) is 23⋅3 and the gcd of (c,d) is 2⋅33. However, the gcd of (b,c)=22⋅32 (meaning both are divisible by 36). Therefore, a is only divisible by 31 (and no higher power of 3), while d is divisible by only 反馈 收藏 ...
However, the gcd of (b,c)=22⋅32 (meaning both are divisible by 36). Therefore, a is only divisible by 31 (and no higher power of 3), while d is divisible by only 21 (and no higher power of 2). Thus, the gcd of (a,d) can be expressed in the form 2⋅3⋅k for ...
2018-02-23 20:36:43.774440+0800 YSC-GCD-demo[19929:5005567] 3---<NSThread: 0x60000026f200>{number = 4, name = (null)} 2018-02-23 20:36:43.774440+0800 YSC-GCD-demo[19929:5005565] 1---<NSThread: 0x600000264800>{number = 3, name = (null)} ...
36. 输出结果: 2018-02-23 20:34:55.095932+0800 YSC-GCD-demo[19892:4996930] currentThread---<NSThread: 0x60400006bbc0>{number = 1, name = main} 2018-02-23 20:34:55.096086+0800 YSC-GCD-demo[19892:4996930] syncConcurrent---begin
36. 37. 38. 39. 40. 41. 42. 43. 44. 45. 46. 47. 48. 49. 50. 51. 在GCD 中有两种队列:串行队列和并发队列。两者都符合 FIFO(先进先出)的原则。两者的主要区别是:执行顺序不同,以及开启线程数不同。 串行队列(Serial Dispatch Queue): 每次只有一个任务被执行。让任务一个接着一个地执行。
gcd(b,c)=36, gcd(c,d)=54, and 70<gcd(d,a)<100. Which of the following must be a divisor of a?( ) A.5 B.7 C.11 D.13 E.17 相关知识点: 试题来源: 解析 D 结果一 题目 Let a,b,c and d be positive integers such that gcd(a,b)=24, gcd(b,c)=36, gcd(c,d)=54,...
Gasket is the structure of a double sealing gasket and has a signal hole. When the medium leaks first, it can be released through the signal port and solve the problem in advance, so as not to cause the mixing of the two media...
In the process we prove some apparently new results on Jordan's totient function. We also prove that these polynomials are irreducible, apart from an obvious linear factor, whenever \\(n\\) is a power of a prime, and conjecture that this holds for all \\(n\\) ....