百度试题 结果1 题目 The following function is a rational function with a horizontal asymptote with equation y=1(x^2-3). ___ 相关知识点: 试题来源: 解析 ✓ 反馈 收藏
Not only does a rational function not have to have vertical asymptotes, but it doesn't have to have a horizontal asymptote, either! A rational function only has a horizontal asymptote if the degree of its denominat...
百度试题 结果1 题目Write the equation of the horizontal asymptote for function. 相关知识点: 试题来源: 解析反馈 收藏
If y=a is a horizontal asymptote of the function y=f(x), then EITHER limlimits _(x→ ∞ )f(x)=a OR limlimits _(x→ -∞ )f(x)=a. Because either of these is sufficient for a horizontal asymptote at y=a, (A) might be true, but does not have to be true. (B) is one ...
Plot a function with its horizontal asymptote: In[47]:= Out[47]= In[48]:= Out[48]= PointStyle(1) Make the points bigger: In[49]:= Out[50]= In[51]:= Out[52]= PowerBehavior(1) By default, the Wolfram Language returns the principal root of a number. If the number is real an...
I can't seem to find an irrational function with the 2 horizontal asymptotes y=1 and y=5.I've looked everywhere and tried all I know, I keep getting 2 asymptotes that the contrary of each other eg. y=1 and y=−1.(The function can't be a composition of 2 functio...
k is the horizontal asymptote Take a look at the function: f(x)=x+7 The inverse of this function is: 1x+7 This is almost in the standard form for reciprocal functions: a = 1 x = x h = -7 k = ? Since there are no other terms in this equation, it is implied...
Write an equation for a rational function with: vertical asymptotes at x = -6 and x = -3, x-intercepts at x = 1 and x = 2, horizontal asymptote at y = 7. Find the horizontal asymptotes, if any, of the following rational functions: a. r_1(x) = \frac{2x^6-5x^4+3x^3-10...
百度试题 结果1 题目Sketch the graph of the function.Identify the horizontal asymptote. f (t) =2^(-t^2) 相关知识点: 试题来源: 解析 Horizontal asymptote: y=0反馈 收藏
Horizontal asymptotes are the numbers that "y" approaches as "x" approaches infinity. For instance, as "x" approaches infinity and "y" approaches 0 for the function "y=1/x" -- "y=0" is the horizontal asymptote. You can save time in finding horizontal asy