If a functiong is decreasing on the interval (−∞,a), increasing on the interval (a,∞), and g(a)=b, thenA:bis a minimum valueB:bis a maximum valueC:ais a maximum valueD:ais a minimum value 相关知识点: 试题来源: 解析 A None ...
Let functionf be an even function and decreasing on the closed interval [ 1,2]. Which of the following functions are increasing on &−2,−1]?I.−f(x)II.f(−x)III.−f(−x)A:III,onlyB:IandII, onlyC:II,onlyD:I,only 相关知识点: 试题来源: 解析 C None 反馈 收藏...
Where is the increasing interval?The derivative of a function may be used to determine whether the function is increasing or decreasing on any intervals in its domain. If f′(x) > 0 at each point in an interval I, then the function is said to be increasing on I....
Find the interval on which the functionf(x)=x4−50x2+9is decreasing. Question: f(x)=x4−50x2+9 Increase and Decrease of a function: f′(x) f″(x)<0 Answer and Explanation:1 f(x)=x4−50x2+9 f′(x)=4x3−100x
2. Interval (e,∞): - Choose a test point, say x=100: f′(100)=1−log1001002=1−4.610000=−3.610000<0 Thus, f(x) is decreasing in the interval (e,∞). Step 4: ConclusionThe function f(x)=logxx is:- Increasing on the interval (0,e)- Decreasing on the interval (e,∞...
百度试题 结果1 题目Identify the interval(s) where the function is (1) increasing (2) decreasing (3)constant 相关知识点: 试题来源: 解析 (1)(-∞,-3) ∪ (-1,3) (2)(-3,-1) (3)(3,∞) 反馈 收藏
Plug each test point into the derivative of the function and evaluate. If the test point gives a positive output, then the function is increasing on the interval from which it came. If the test point gives a negative output, then the function is decreasing on the ...
and to the initial condition u(x,0) = f(x); the given functions f: [0,1] → R, : R → R are assumed to be smooth, (0) = 0, satisfies the coercivity assumption () > c 2 , for some constant c > 0 and for R, and is assumed to be decreasing on an interval (a,b) wi...
Determine the interval(s)on which the function is(strictly)decreasing. Write your answer as an interval or list of intervals. When writing a list of intervals, make sure to separate each interval with a comma and to use as few interv...
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