LEFT OUTER JOIN ( SELECT1AS [test], [t1].[Id], [t1].[GroupName] FROM [Group] AS [t1] ) AS [t2] ON [t0].[GroupId] =([t2].[Id]) Linq to Sql:from uinUsers join ginGroups on u.GroupId equals g.Id into Grpfrom grpinGrp.DefaultIfEmpty()selectnew { GroupName=(grp==null)...
2、左连接(LEFT JOIN) //Sql: SELECT g.GroupName,u.UserName FROM GroupName g LEFT JOIN User u ON g.Id = u.GroupId //Linq to Sql: from g in Groups join u in Users on g.Id equals u.GroupId into Grp from grp in Grp.DefaultIfEmpty() select new { GroupName=g.GroupName, UserName...
Among all the sources I've studied on LINQ I haven't met an answer to one question. How to implement FULL OUTER JOIN construct using LINQ? Making LEFT OR RIGHT outer join is a known method, but FULL is a mystery. I'm using LINQ to SQL. It seems to me like it's not supported...
Like Left and Right Join, Full Outer Join is not supported directly with LINQ, but you can write a query to produce the same results. Currently, the simplest way to do this is to concatenate three subqueries together. The first query provides the results where the “right” table has a ...
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Thesecond curly bracerepresents aninitialization blockthat we have seen in it as a class for initialization. When we use the initialization block for an anonymous inner class it becomes Java double brace initialization. Theinner classhas a reference to the enclosing outer class. We can use the ...
If LINQ to SQL or other, the query processor might not support safe navigation or other operations. You'd have to use the conditional operator to conditionally get the values. i.e., var leftOuterJoin = from first in firstNames join last in lastNames on first.ID equals last.ID into ...
C# 实现FULL JOIN 效果 参考:https://dotnettutorials.net/lesson/full-outer-join-in-linq/ 思路就是先left join 再right join,最后union 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
LINQ 全联接 FULL JOIN (二) voidFullOuterJoin() {varfirstNames =new[] {new{ ID =1, Name ="John"},new{ ID =2, Name ="Sue"}, };varlastNames =new[] {new{ ID =1, Name ="Doe"},new{ ID =3, Name ="Smith"}, };varleftOuterJoin =fromfirstinfirstNames...
keys.UnionWith(bdict.Keys);varjoin =fromkeyinkeys let xa=adict.OuterGet(key) let xb=bdict.OuterGet(key)selectprojection(xa, xb, key);returnjoin.ToList(); }internalstaticIList<TR> FullOuterJoin<TA, TB, TK, TR>(thisIEnumerable<TA>a, ...