I am able to grant friendship to class B and to function "function" in class A without forward declaring class B, or function "function". Now, if I want to grant friendship to the two member functions in class B it doesn't work if I don't define class B before defining class A: ...
Only the friend function (i.e., declared as a friend) can access the private data of members of the friendship-granting class. Let’s see the implementation of the friendship concept in C++. #include <iostream> using namespace std; class ABC { int privateMember; public: ABC(int private...
class ONE; class TWO { public: void print(ONE& x); }; class ONE { int a, b; friend void TWO::print(ONE& x); public: ONE() : a(1), b(2) { } }; void TWO::print(ONE& x) { cout << "a is " << x.a << endl; cout << "b is " << x.b << endl; } int mai...
I have this program with a friend function defined inside the class, that compiles with gcc and clang but is rejected by msvc. #include<iostream>template<typenameT>classOuter{structInner;friendvoidfoo(); };template<typenameT>structOuter<T>::Inner {friendvoidbar(Inner){//gcc ...
class HasFriends { friend int ForwardDeclared::IsAFriend(); // C2039 error expected }; The preceding example enters the class name ForwardDeclared into scope, but the complete declaration (specifically, the portion that declares the function IsAFriend) isn't known. the friend declaration in clas...
CMain Class is the base class that is initialized in main function. CA Class is the base class that is initialized in CMain::CMain(). CMain Class is always public while CA Class is always private. I have placed "friend void CA::Run_A(void)" in CMain Class. CMain::Run() functio...
friend return_type class_name::function_name (arguments); // for a member function of another class class intellipaat{ friend int intellipaat_Function(paat); statements; }In this example, friendFunction is declared a friend of the MyClass class and can access its private member, privateData....
The name of a friend function or class first introduced in a friend declaration is not in the scope of the class granting friendship (also called theenclosing class) and is not a member of the class granting friendship. The name of a function first introduced in a friend declaration is in...
class className { friend returnType functionName(arguments); } The keyword “friend” is placed only in the function declaration of the friend function and not in the function definition. When the friend function is called neither the name of the object nor the dot operator is used. However,...
testClass.cpp:5: template-id `someFunction<T>' in declaration of primary template U:\test> Following the compiler's suggestion removes the warning but still yields the following error: U:\test>g++ -Wno-non-template-friend -c testClass.cpp testClass.cpp:5: template-id `someFunction<T>' ...