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(Pokemon): # overrides the stringPokemon() function on 'Pokemon' class def stringPokemon(self): print(f"Grass type pokemon name is {self.name}") poke1 = GrassType('Bulbasaur', 'Grass') poke1.stringPokemon poke1.stringPokemon() poke2 = Pokemon('Charizard', 'Fire') poke2.stringPokemon...
I gave myself a challenge about manipulating lists and now I'm stuck. Here's my problem: I have two lists of strings. names =["Bulbasaur", "Ivysaur", "Venusaur", "Charmander", "Charmeleon", "Charizard", "Squirtle", "Wartortle", "Blastoise"] numbers = ["#1 ", "#2 ", "#3 "...
fastSecond, you can set the customWords property of your request to be an array of unusual strings that your app is likely to come across – words that Vision might decide aren’t likely because it doesn’t recognize them:request.customWords = ["Pikachu", ...