Why can't I forward declare myotherstruct? Jul 19, 2012 at 11:44am Need4Sleep(570) what error do you get? EDIT: whoops, didnt see Try this: 1 2 3 4 5 typedefstructmystruct {inti;doublef; } myotherstruct; Last edited onJul 19, 2012 at 11:47am ...
typedef struct Bar Bar; // and a C99-only comment that \ we hope is not so long that it wraps around and, oh dear, \ good thing each of these lines ends with a backslash-newline void Foo(Bar* b); struct Bar; typedef struct Bar Bar; This goes wrong because in C (unlike C++)...
This means that in order to forward-declare std::wstring you'd have to forward-declare std::char_traits<> and std::basic_string<> inside namespace std. Because (apart from a few exceptions) the standard forbids adding definitions or declarations to namespace std (17.4.3.1/1) ultimately yo...
1 struct forward declaration in C 1 invalid forward declaration of struct 6 C forward declaration of struct in header 1 compiler giving error on forward struct declaration 2 Why does forward declaration of struct not work? 1 Cannot forward declare a typedef? 1 Forward Struct Declaration in...
Don't use that old C-style typedef stuff. Just declare the struct like this: struct STREAM { /* Used from v5.0 */ DWORD ID; /* unique ID of stream, remains unchanged in drawing */ DWORD VertxCount; /* Number of vertices on stream */ ...
typedef struct mbedtls_ecp_keypair MY_ECC_KEY. (This already works for some structs, like mbedtls_x509_crt) I think this would be useful outside my case as I imagine there are many applications that support mbedtls as well as another implementation, and being able to forward declare types ...
SLATE_BEGIN_ARGS的声明 #defineSLATE_BEGIN_ARGS( WidgetType ) \public: \structFArguments :publicTSlateBaseNamedArgs<WidgetType>\ { \ typedef FArguments WidgetArgsType; \ FORCENOINLINE FArguments() SLATE_END_ARGS():无参宏 SLATE_END_ARGS的声明 ...
You can't forward-declare a nested class like that. Depending on what you're trying to do, maybe you can use a namespace rather than a class on the outer layer. You can forward-declare such a class no problem: namespace Outer { struct Inner; }; Outer::Inner* sweets; // Outer::...
As far as I know, the typedef trick in C is used so that you do not need to use the keyword "struct" when declaring objects of that type. For example, given the definition: struct RTL_CRITICAL_SE CTION { /* members */ }; In C, you would have to declare an object of this type...