后半段好像得区分一下 if len(l)<=8: for j in range(len(l)): print(l[j],ll[j]) else: l_8 = l[-8:] ll_8 = ll[-8:] for i in range(len(l_8)): print(l_8[-8:][i],ll_8[i]) 2 02-19 08:14 腾讯_大数据高性能开发(准入职员工) ...
a=input('') for i in range(0,len(a)): if a[i] in ['a','b','c']: j=2 elif a[i] in ['d','e','f']: j=3 elif a[i] in ['g','h','i']: j=4 elif a[i] in ['j','k','l']: j=5 elif a[i] in ['m','n','o']: j=6 elif a[i] in ['p','...
range()函数内可以填入三个参数,第三个参数是步进值(步进值默认为1): >>> range(0,10,2) [0, 2, 4, 6,8] 1. 2. range函数的参数和结果也并非一定要是正数或是递增的,好比下面两个例子: >>> range(-4,4) [-4, -3, -2, -1, 0, 1, 2, 3] >>> >>> range(4,-4,-1) [4, 3...
For 变量 in range (): 语句 For I in range (n,m): 范围: n,m-1 For… else..(可以嵌套使用) for I in range (): else: 对于字符串,可以利用 s1=“abcd” for i in s1: print(i) 表示从字符串里面依次取出s1的元素 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 只有当fo...
用小括号的时候，L被当作一个函数了，而L在这是个list，所以不可调用
for i in range(1, 101，1):print i range(1, 101)表示从1开始，到101为止（不包括101），取其中所有的整数。for i in range(1, 101)就是说，把这些数，依次赋值给变量i。相当于一个一个循环过去，第一次i = 1，第二次i = 2，……，直到i = 100。当i = 101时跳出循环。
# for i in range(len(l)): # print(i,l[i]) # # for x in l: # print(l) 1.8、for+continue # for i in range(6): # 0 1 2 3 4 5 # if i == 4: # continue # print(i) 1.9、for循环嵌套:外层循环循环一次,内层循环需要完整的循环完毕 ...
->4,3,2,1#逆序foriinrange(4,-1,-1):printi ->4,3,2,1,0 方法三:利用下标切片逆序 a =range(4)#或者a = [0,1,2,3]formina[::-1]:printm ->3,2,1,0 拓展: 逆向访问特定区间值: l= [1,3,5,6,7,8] l[::-1][:3]#逆序后访问前三位 orl[-3:][::-1]#先访问后三位后...
GIT-BUILD-OPTIONS.in GIT-VERSION-FILE.in GIT-VERSION-GEN INSTALL LGPL-2.1 Makefile README.md RelNotes SECURITY.md abspath.c abspath.h aclocal.m4 add-interactive.c add-interactive.h add-patch.c advice.c advice.h alias.c alias.h alloc.c alloc.h apply.c ...
withtqdm(total=100)aspbar:foriinrange(10):sleep(0.1)pbar.update(10) If the optional variabletotal(or an iterable withlen()) is provided, predictive stats are displayed. withis also optional (you can just assigntqdm()to a variable, but in this case don't forget todelorclose()at the ...