foreach_vector.cpp #include <iostream> #include <vector> int main() { std::vector<int> nums { 1, 2, 3, 4, 5, 6, 7 }; for (auto num: nums) { std::cout << num << std::endl; } } We go over the vector of integers. ...
在C++中,foreach算法并不是一个标准的库函数。但是,您可以使用C++11中引入的范围循环(range-based for loop)来实现类似的功能。范围循环允许您遍历一个容器(如std::vector、std::array等)中的所有元素,而无需手动管理索引或迭代器。 以下是一个使用范围循环遍历std::vector中所有元素的示例: 代码语言:cpp 复制...
// main.cpp#include"alg_for_each.h"voidmain( ){vector<int> v1;vector<int>::iterator Iter1;// Constructing vector v1inti;for( i =-4; i <=2; i++ ) { v1.push_back( i ); }cout<<"Original vector v1 = ( ";for( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter...
在这个例子中,我们使用范围循环遍历一个std::vector,当遇到元素3时,我们删除该元素并继续循环。这样就可以在循环过程中中断或者修改容器元素。 相关搜索: 将for循环转换为std :: for_each 在std :: for_each中调用std :: function std::for_each似乎正在清除std::string ...
threads.push_back(std::thread(increase_global,1000));//分开写: thread t()// thread.push_back(t) 就无法编译通过,因为要用到operator= ,而 thread只允许move semnantics,就是只允许右值引用类似的 对于c++11里的foreach ,可以解释为 http://en.cppreference.com/w/cpp/language/range-for{ ...
vector<int>v={3,1,4,1,5,9};for(autoiter=v.begin();iter!=v.end();++iter)std::cout<<*iter<<' ';std::cout<<"\n\n""5) init-statement can be an expression:\n";intn=0;for(std::cout<<"Loop start\n";std::cout<<"Loop test\n";std::cout<<"Iteration "<<++n<<'\n'...
Did C++11 range-based for loops make for_each obsolete? The answer is No. Find out when to use one or the other and keep your code expressive.
Write afor-loop that squares a number for values ofnbetween 1 and 4. forn = 1:4 n^2end ans = 1 ans = 4 ans = 9 ans = 16 Input Arguments collapse all j—Starting vector value scalar Starting vector value, specified as a real numeric scalar. Ifj < kso that the output vector is...
初学者若想要删除std::vector内的element,第一个想到的就是用for loop,若该iterator的值是我要删的,就erase 1 // Compile OK, but run-time error!! 2 for(std::vector<int>::iterator iter = ivec.begin(); iter != ivec.end(); ++iter) ...
#include <algorithm>#include <iostream>#include <vector>intmain(){std::vector<int>v{3,-4,2,-8,15,267};autoprint=[](constint&n){std::cout<<n<<' ';};std::cout<<"before:\t";std::for_each(v.cbegin(), v.cend(), print);std::cout<<'\n';// increment elements in-placestd...