products C. equilibrium state D. reverse reaction 相关知识点: 试题来源: 解析 B。平衡常数大说明反应更倾向于生成产物。选项 A“reactants”表示反应物;选项 B“products”表示产物;选项 C“equilibrium state”表示平衡状态;选项 D“reverse reaction”表示逆反应。所以答案是 B。反馈 收藏 ...
Equilibrium for a general reactiong) N
If at equilibrium there are 1.0 mol of A,2.0 mol of B, 6.0 mol of C,and 20 mol of D in al. 0 L vessel. A. 0 B. 0 C. 0 相关知识点: 试题来源: 解析 K=[C][D]/[A][B]=(6.0 mol/L)(20 mol/L)/(1.0 mol/L) (2.0mol/L) =60 ...
For the reaction AB(g)hArrA(g)+B(g), at equilibrium AB is 20% dissociated at a total pressure of P, The equilibrium constant K(p) is related to tha total pres
解析 解 电极反应 Cu(acu )+e=Cu(s) \varphi_(Cu)⋅ρ_(Cu)=0.521V Cu2+(acu2)+2e-=Cu(s) e \varphi_(Cu)^2⋅x_(i1)=0.337V E =2-2=-2/=0.521-0. 337 =0.184(V) △G=-nFE^-=-2.303RTlgK^0 lgK^θ=(2*9648*0.184)/(2.303*8.314*298)=6.22 K^θ=1.66*10^6 ...
1. What is the value of the equilibrium constant at 25℃ for the reaction ( refer to the table of standard electrode potential):I1(s)+2Br(aq)=2I (aq)+Br2(1)? 相关知识点: 试题来源: 解析 Solution \varphi^θ(I_2/I^-)=0.5355V_(i4)^θ(Br_2/Br^-)=1.066V 2x(0. 5355V-1....
1. What is the value of the equilibrium constant at 25 C for the reaction (refer to the table of standard electrode potential) : I2(s)+ 2Br(aq)=2I (aq)+ Br2 (1)? 相关知识点: 试题来源: 解析 1.1. 15*10^(-1) 反馈 收藏 ...
2HI(g) hArr H(2)(g)+I(2)(g), K=1//54.8 At equilibrium, [HI]=0.5 mol L^(-1), [H(2)]=[I(2)]=xmol L^(-1) :. K=(x xx x)/((0.5)^(2))=1/54.8 (Given) This gives x=0.068, i.e., [H(2)]=[I(2)]=0.068 mol L^(-1).
The device and method for the equilibrium reaction 优质文献 相似文献Peritoneal dialysis method This invention relates to an improved method for conducting peritoneal dialysis with a decreased total volume of dialysis fluid used and increased efficacy parameters such as ultrafiltration rate, urea clearance ...
Question: The equilibrium constant for the reaction below decreases from 1.8×105 at 703K to 23 at 1273K2NO(g)+O2(g)⇄2NO2(g)a) Calculate ΔG°?rAn for the reaction at 703K using K=1.8×105 at that temperature.b)...