Find the vertex, axis, focus, directrix, tangent at the vertex, and length of the latus rectum of the parabola2y2+3y−4x−3=0. View Solution Find the vertex, focus and directix and latus rectum of the parabola. (y+3)2=2(x+2) ...
Example: This is a graph of the parabola with all its major features labeled: axis of symmetry, focus, vertex, and directrix.See alsoConic sections, foci of an ellipse, foci of a hyperbola, focal radiusthis page updated 15-jul-23 Mathwords: Terms and Formulas from Algebra I to ...
To solve the problem of finding the vertex, focus, and directrix of the parabola given by the equation
Focus: {eq}(h,k+a) {/eq} Directrix: {eq}x = h {/eq} Answer and Explanation: a. {eq}(y-9)^2 = 20 (x - 9) \\ (y-9)^2 = 4(5(x - 9)) {/eq} We have: Vertex: {eq}(9,9) {/eq} Focus: {eq}(9,14) {/eq} Directrix: {...
Find the coordinates of the vertex and focus, then find the equation of the directrix for the given equation.x= − 4x − 2y = 0Vertex :Focus :Directrix : 相关知识点: 试题来源: 解析 Vertex : (2,−2); Focus : (2,−); Directrix : y = −Vertex : (2,−2); Focus ...
Find the vertex, focus, and directrix of the parabola and sketch its graph. 3x2+8y=0 Vertex Form of a Parabola: By now we are quite used to seeing the standard form for a parabola as y(x)=ax2+bx+c But there are other, and depending on context sometimes mor...
(x)=ax2+bx+cwhere a, b, and c are constants that will shape the parabola. The major parts of the parabola are thefocus,vertex, and thedirectrix. The parabola comprises equidistant points from the focus (single point of the parabola) and the directrix (line of the parabola). Vertex is...
题目 Use the information from the table to graph the parabola along with its focus, directrix, and axis of symmetry.(x-2)^2=-4(y-3)Vertex: p= Opens Focus: Directrix: Axis of symmetry: 相关知识点: 试题来源: 解析 (2,3); -1; down; (2,2); y=4; x=2; 反馈 收藏 ...
1,2,3,4,5,6,7 and 8 Find the vertex, focus, and directrix of the parabola and sketch its graph. 2x2-16x-3y+38=0There are 2 steps to solve this one. Solution Share Step 1 Solution: Given that Equation of parabola, 2x2−...
Since the directrix is vertical, use the equation of a parabola that opens up or down. ( ((x-h))^2=4p(y-k)) Find the vertex. ( (2,-1/2)) Find the distance from the focus to the vertex. ( p=3/2) Substitute in the known values for the variables into the equation(...