Directrix=y=4 Step 5: Find the axis of the parabolaThe axis of the parabola is the line that runs vertically through the vertex and focus. For this parabola, the axis is the y-axis:Axis=x=0(or the y-axis) Step 6
To solve the problem of finding the vertex, focus, directrix, axis, and length of the latus rectum of the parabola given by the equation <sp
Example: This is a graph of the parabola with all its major features labeled: axis of symmetry, focus, vertex, and directrix.See alsoConic sections, foci of an ellipse, foci of a hyperbola, focal radiusthis page updated 15-jul-23 Mathwords: Terms and Formulas from Algebra I to ...
Find vertex, focus, and directrix of the parabola 2y2+4x−2x+1=0. Parabola and its Properties: A parabola is the locus of a point that moves in such a way so that the distance from a fixed point called focus is always equal to the distance from a fixed line known...
Find the coordinates of the vertex and focus, then find the equation of the directrix for the given equation.x= − 4x − 2y = 0Vertex :Focus :Directrix : 相关知识点: 试题来源: 解析 Vertex : (2,−2); Focus : (2,−); Directrix : y = −Vertex : (2,−2); Focus ...
Find the vertex, focus, and directrix of the parabola and sketch its graph. 3x2+8y=0 Vertex Form of a Parabola: By now we are quite used to seeing the standard form for a parabola as y(x)=ax2+bx+c But there are other, and depending on context sometimes mor...
(x)=ax2+bx+cwhere a, b, and c are constants that will shape the parabola. The major parts of the parabola are thefocus,vertex, and thedirectrix. The parabola comprises equidistant points from the focus (single point of the parabola) and the directrix (line of the parabola). Vertex is...
题目 Use the information from the table to graph the parabola along with its focus, directrix, and axis of symmetry.(x-2)^2=-4(y-3)Vertex: p= Opens Focus: Directrix: Axis of symmetry: 相关知识点: 试题来源: 解析 (2,3); -1; down; (2,2); y=4; x=2; 反馈 收藏 ...
The directrix of the parabola is the horizontal line perpendicular to the axis of symmetry. If the axis of symmetry is {eq}x- {/eq} axis, then the directrix of the parabola with the focus {eq}a {/eq}, and the vertex {eq}(h,k) {/eq} is, {eq}x=h \pm a {/eq}. Similarly...
Since the directrix is vertical, use the equation of a parabola that opens up or down. ( ((x-h))^2=4p(y-k)) Find the vertex. ( (2,-1/2)) Find the distance from the focus to the vertex. ( p=3/2) Substitute in the known values for the variables into the equation(...