二、原因 使用jieba分词时遇到了float类型的数据,需要进行转换。 回到顶部 三、解决方案 修改下输入的格式,转换下: jieba.lcut(str(str1))
问题出在这里:u_score=u_score.append(lose) 要知道,append方法是没有返回值的。也 3.x运行的坑:AttributeError: 'str' object has no attribute 'decode' line 146, in last_executed_query query = query.decode(errors='replace') AttributeError: 'str' object has no attribute 'decode' 报错截图: 逃...
浮点对象没有属性解码 float object has no attribute decode 浮点对象没有属性解码
sql_local ="""INSERT INTO customer_1.pay_and_display (plate, machine_id, ticket_datetime, expiry_datetime, ticket_name, ticket_price) VALUES ("%s", "%s", "%s", "%s", "%s", "%s") """% (vrm, location_id, entryDatetime, expiryDatetime,"RINGOtest",0)printsql_local cursor.execute...
这个问题感觉很奇怪,报错的地方前后都没有数值,但就是报错。所以在读该文档的时候就将该dataframe格式转为str,就没有问题了 train = pd.read_csv("train.csv",encoding='utf-8',dtype=str) train=train.astype(str)###这个地方是解决方案 for index, rowin train....
原因python3读取csv文件的默认编码为unicode,unicode并不是编码格式,而是字符集,它包含了世界上目前所有的符号,所以unicode没有decode属性 ...
AttributeError: 'float' object has no attribute 'decode' 面对AttributeError: 'float' object has no attribute 'decode'错误,用.astype(str)将数据转化为字符串类型即可
结果总是出现“AttributeError: 'float' object has no attribute 'decode',为了解决这个问题,把这个series变成str之后又无法loop,请问我应该怎么处理呢?谢谢! Can you be more specific on how to use your idea, Can't understand. Thank you in advance . ...
AttributeError: ‘float’ object has no attribute ‘decode’ 读取存储为.csv格式的文件,报属性错误。 解决方法:在read_csv后面加上.astype(str) 有编码解码问题,可以尝试 file = open(path, encoding=‘gb18030’, errors=‘ignore’) file = open(‘D://Document And Settings3/lqz/Desktop/Walden2.txt...
ValueRaidermentioned this issueNov 3, 2022 ValueRaidermentioned this issueNov 10, 2022 Sign up for freeto join this conversation on GitHub. Already have an account?Sign in to comment Assignees No one assigned Labels None yet Projects None yet ...