``` import java.util.ArrayList; import java.util.Arrays; import java.util.List; /** * Source : https://oj.leetcode.com/problems/flatten-binary-tree-to
LeetCode 114题的解题思路是什么? 二叉树扁平化成链表的算法有哪些? 要求:Given a binary tree, flatten it to a linked list in-place.将二叉树转化为平坦序列的树。比如: 结题思路: 该题有个提示,转化后的树的序列正好是二叉树前序遍历所得到的序列,所以,该题第一个思路就是利用前序遍历的方式来做。
The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal. 题目大意就是让你将一个二叉树转化为一个只有右子节点的扁平树,且每一个节点的右孩子都是他前...
packageleetcode/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */// 解法一 非递归funcflatten(root*TreeNode){list,cur:=[]int{},&TreeNode{}preorder(root,&list)cur=rootfori:=1;i<len(list);i++{cur.Left=nil...
[LeetCode]Flatten Binary Tree to Linked List Question Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 1. 2. 3. 4. 5. The flattened tree should look like: 1 \ 2
https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ 题目: Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 ...
Given a binary tree, flatten it to a linked list in-place. For example, Given 代码语言:javascript 代码运行次数:0 运行 AI代码解释 1/\25/\ \346 The flattened tree should look like: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 递归法 思路 相当于一次先序遍历, 将先访问的点存储在数组里, 下一个访问的节点为之前访问的点的右子树 ...
LeetCode—108. Convert Sorted Array to Binary Search Tree 题目 https://leetcode.com/problems/convert-sorted-array-to-binary-search-tree/description/ 将一个递增数组转化为平衡二叉搜索树。平衡二叉搜索树首先是一个二叉搜索树,其次要求每一个节点的左右... ...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public void flatten(TreeNode root) { rightFlatten(root); ...