105. The answers to these clues(线索) are all five-letter words. The letters in the pink squares make up anew word. It's an animal.① Schoolroom group①② Our planet②a③ Not man; female③④ We use itto draw straightlines.④⑤ Not big;tiny⑤Sm ...
about above 5 letter words with... : A-B-C-D-E-F-G-H-I-J-K-L-M-N-O-P-Q-R-S-T-U-V-W-X-Y-Z When we play scrabble of crosswords, we often need5 letter words. Find below some 5 letter words popular searches :
【解析】答案:a.ounced.growne.climbf.guessg.sneak翻译:a.盎司(重量单位);少量,一点点c.带来d.成熟的;长大的e.攀登,(太阳等)徐徐上升f.猜g.偷偷地走;偷拿;偷走 结果一 题目 Can you make five-letter words with these letters?a. E U CONb.EE UNQc. IB N RGd. G WNORe. BIL C Mf. GSUS...
Only one of the five-letter words below can be pu into a different order which spells a five-etter English word.What's this word?JUCBI NEACH METAP TPHED MUDOP ABUMG ERVIC 相关知识点: 试题来源: 解析 【解析】102.DEPTH.通过重新排列TPHED可以获得此词 ...
He wrote a ___ letter. A. five-hundreds-words B. five-hundreds-word C. five-hundred-word D. five-hundred-words 相关知识点: 试题来源: 解析 数字用连字符“-”连接作复合定语修饰名词时,连字符连接的名词和数词都必须用单数。故答案为C。 反馈 收藏...
(16分)1.The little boy wrote aletter to his uncle.A.five-hundred wordsB.five-hundred-wordC.five hundreds wordsD.five-hundreds-wordⅡI.单项选择.(16分) , 1.The little boy wrote a__letter to his uncle. , A.five-hundred words B.five-hundred-word , C.five hundreds words D.Five-...
I wrote a ___letter to my pen friendA.five-hundred-wordB.five-hundreds-wordC.five-hundred-wordsD.five-hundreds-words顺便说明一下为什么 答案 选择A.因为使用了连接符号,其中所有的单词都要改为原形,这个句子填上正确答案后的意思就是:我给我的笔友写了一封500词的信.相关推荐 1I wrote a ___letter...
B. (1966). The recognition of tachistoscopically presented five-letter words as a function of digram frequency. Journal of Verbal Learning and Verbal Behavior, 5, 208-209.Biederman, G. B. Supplementary report: The recognition of tachisto- scopically presented five-letter words as a function...
How many different five-letter permutations can be formed from the letters in the word "category"? Permutation: The formula for permutation is mathematically represented as, {eq}\displaystyle P(n,r)=\frac{n!}{(n-r)!} {/eq} where {eq}\displaystyle n {/...
⋅4 "words" beginning with each of the first four letters alphabetically. From there, there are 3!⋅3 with U as the first letter and each of the first three letters alphabetically. After that, the next "word" is USAMO, hence our answer is 4⋅4!+3⋅3!+1=115. Let A=1...