classSolution{public:intstrStr(string haystack, string needle){/* find the first needle in haystack */intret =-1, pos =0;intneedle_len = needle.size();//bool sign = false;for(inti =0; i < haystack.size(); ++i){if(haystack[i] == needle[pos]){if(pos == needle_len -1)return...
Input:haystack = "sadbutsad", needle = "sad"Output:0Explanation:"sad" occurs at index 0 and 6. The first occurrence is at index 0, so we return 0. Example 2: Input:haystack = "leetcode", needle = "leeto"Output:-1Explanation:"leeto" did not occur in "leetcode", so we return ...
Given two stringsneedleandhaystack, return the index of the first occurrence ofneedleinhaystack, or-1ifneedleis not part ofhaystack. implSolution{pubfnstr_str(haystack:String,needle:String)->i32{lethlen=haystack.len();letnlen=needle.len();ifhlen<nlen{return-1;}foriin0..=(hlen-nlen){if&...
Return the index of the first occurrence of needle in haystack, or-1ifneedleis not part ofhaystack. Clarification: What should we return whenneedleis an empty string? This is a great question to ask during an interview. For the purpose of this problem, we will return 0 whenneedleis an e...
s = "loveleetcode", return 2. Note: You may assume the string contain only lowercase letters. 思路 1. use int array to simplify a hashmap 2. one pass to mark each char's occurrence 3. second pass to check 1st index whose char's occurrence == 1 ...
If the target is found, it continues searching in the left half (right = mid - 1), otherwise, it searches in the right half (left = mid + 1). The loop exits when left > right, and left will point to the first occurrence of the target or the insertion point if the target is ...
- LeetCodeleetcode.com/problems/find-the-index-of-the-first-occurrence-in-a-string/description/ 解题思路 二重循环,没什么特别的 class Solution { public: int strStr(string haystack, string needle) { int index = 0; bool flag = true; for(int i = 0; i < haystack.size(); i++) { ...