Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. class Solution(object): def ...
Leetcode 34. Find First and Last Position of Element in Sorted Array 在一个有序数组中找到第一个和最后一个元素,程序员大本营,技术文章内容聚合第一站。
first,last=mid,midwhilel <=first: fm= (first+l) // 2ifnums[fm] <target: l= fm + 1else: first= fm -1whiler >=last: rm= (last+r) // 2ifnums[rm] >target: r= rm - 1else: last= rm + 1return[first+1,last-1]return[-1,-1]...
排序数组中查找元素的第一个和最后一个位置 Find First And Last Position of Element in Sorted Array 给定一个非递减排序数组nums和目标target.找到target在数组中的开始位置和结束位置。如果数组中不存在这个数,返回[-1,-1] nums = [5,7,7,8,8,10], target = 7 [1,2] 思路 这个要求,查到target的第...
Given an array of integersnumssorted in ascending order, find the starting and ending position of a giventargetvalue. Your algorithm’s runtime complexity must be in the order ofO(logn). If the target is not found in the array, return[-1, -1]. ...
Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value. If target is not found in the array, return [-1, -1]. You must write an algorithm with O(log n) runtime complexity. 2. Analysis: To solve this problem ...
Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm’s runtime complexity must be in the order of O(log n). If the target is not found in the array, return [-1, -1]. ...
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Memory Usage: 30.5 MB, less than 28.29% of Java online submissions for Find First and Last Position of Element in Sorted Array. class Solution { public int[] searchRange(int[] nums, int target) { int[] result = new int[2];
https://leetcode.com/problems/find-first-and-last-position-of-element-in-sorted-array/ 给定一个有序数组,可能包含有重复元素,问target在数组中的起始位置和结束位置,要求复杂度\(O(logN)\) --- Example 1: Input: nums = [5,7,7,8,8,10], target = 8 Output: [3,4] Example 2: Input...