Integrating speed with respect to time (between the start and finish times) provides you with the total distance traveled during that time: ∫ (✓((dx/dt)²+(dy/dt)²)))dt. Make sure to use the given t-values as the boundaries of the integral. Upvote • 0 Downvote Add comment...
I haven't taken calculus yet. Okay. So it looks like an exact solution via differential equation is not going to happen. Some type of approximation will be required. One thing you might consider is doing some successive approximations to close in on a reasonable value. For example, ...
Derive the kinematic equations for constant acceleration using integral calculus. Use the integral formulation of the kinematic equations in analyzing motion. Find the functional form of velocity versus time given the acceleration function. Find the functional form of position versus time gi...
2. If a function gives you the distance an object has traveled, what will the first derivative give you? The object's speed The object's acceleration The object's angle The object's total distance covered Create your account to access this entire worksheet ...
We realize our kid wasn’t inadequate because he failed to pass calculus, and our spouse was never the flawed soul we had imagined. Uncle George, who managed to ruin every holiday party, was never really a bad guy, just a troubled soul who warranted compassion. They were all illusions, ...
Total distance traveled (both cars), numerically:297Setting that total and the algebraic equation equal to each other, you get the following equation:6S + 15 = 297First, subtract 15 from both sides. Then you're left with the following equation:6S = 282Divide both sides of that equation by...