代码语言:typescript 复制 constobj={key1:'value1',key2:'value2',key3:'value3',};constsearchKey='key2';constresult=Object.entries(obj).find(([key,value])=>key===searchKey);console.log(result);// ['key2', 'value2'] 在上面的示例中,我们首先定义了一个包含键/值...
interface A { name: string } interface B { age: number } let arr: Array<A|B> = [{name: 'jack'}] arr.push({ age: 17}) function testA(value: A|B): value is A { return 'name' in value && value.name === 'jack' } let findA = arr.find<A>(testA) function test(value: ...
typescript find 可选参数 默认值 默认参数 转载 hushuo 2023-08-10 17:25:52 0阅读 javascriptfindjavascriptfind函数 find()方法返回数组中符合的第一个值,效果和swith类似,但是简单很多,用法:array.find(function(currentValue, index, arr),thisValue) 参数: currentValue 必需。当前元素index 可选。当前元素...
First, declare an array of objects, each object with an id and name properties. When it comes to the program’s execution, a function is created with an array, object key, and value. Theforloop is used to iterate through the objects in an array. Each object is checked with the assigne...
在下文中一共展示了findIndex函数的15个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的TypeScript代码示例。 示例1: getFactors ▲点赞 9▼ panelUpgrades.push(panel=>{if(panel.minSpan) {constmax = GRID_COLUMN_COUNT / panel.minSpan;...
Hello, I'm using typescript and got error Property 'value' does not exist on type 'HTMLElement'.ts(2339) any Here is my test it('Should write a login', async () => { const wrapper = shallowMount(LoginForm) const input = wrapper.find( '[d...
typescript find 可选参数 默认值 默认参数 转载 hushuo 2023-08-10 17:25:52 0阅读 javascriptfindjavascriptfind函数 find()方法返回数组中符合的第一个值,效果和swith类似,但是简单很多,用法:array.find(function(currentValue, index, arr),thisValue) 参数: currentValue 必需。当前元素index 可选。当前元素...
简单地说，find并不期望返回promise，因为它不适用于异步操作。它循环遍历数组，直到其中一个元素返回一个...
The problem here is that TypeScript has no representation, at the type level, of the concept of "Array<Ok | Err>, but at least one element is anOk", so.some(isOk)can contribute nothing to the type of the array and thus there's simply not enough information for the compiler to guara...
const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = [...yourArray] yourArrayWithoutDuplicates.forEach((item) => { const i = duplicates.indexOf(item) duplicates = duplicates .slice(0, i) .concat(duplicates.slice(i...